DXC Quants Problems on Ages Quiz 3

Answer:
Let the ages of the 3 brothers in completed years be x, y, z.
x^2 + y^ 2 + z^2 = 325 .......(i)
Clearly, the three numbers have to be less than 18 since the square of 18 itself is 324.
By trial, we see that 325 = 152 + 82 + 62 or 122 + 102 + 92
As the product of the ages is less than 1000, the ages have to be 6, 8, 15
The youngest is 6.

Answer:
According to the question,
9x + 7x + x + 3 × 8 + 4 = 24 × 4
17x + 24 + 4 = 96
17x = 96 – 28
17x = 68
x = 4
Age of the oldest person = 9 × 4 = 36 years

Answer:
Let the age of seema at their silver anniversary = K yrs
18 yrs of marriage = 7 yrs before silver anniversary
Age of seema 7yrs before silver anniversary = K – 7
Seema’S age 25 yrs after silver anniversary = K + 25
K – 7 / K + 25 = 5 / 21
K = 17yrs
Seema’s age on silver anniversary = 17yrs
She was born 25 – 17 yrs = 8 yrs after the marriage.

Answer: 15.48
Let, the present average age of the group = X
Then according to the question,
⇒ 150/100 (X – 5) = X
⇒ X = 15
The required average ‘Y’ = (15 × 60 + 22 + 38)/62 = 15.48

Answer:
Correct Option: C
Let Shikhar’s age = A, Bhuvan’s age = B, and Hardik’s age = C
Then, according to the question,
⇒ A/C = 3/4 ................(i)
⇒ B + 5/ C-1 = 4/3 ................(iI)
⇒ 4 × (C – A) = B + 1 ------------------(iii)
After solving these equations,
⇒ A = 12
⇒ C = 16
Average of ages of Shikhar and Hardik = 12 + 16 / 2 = 14

Answer : 14 years
Explanation:
Let us take Shahid’s age as x, Mira’s age as y, and Ishan’s age as z.
Given, (x+y) = 14 + (y+z)
(x+y) - (y+z) = 14
x-z = 14 years
The difference between Shahid and Ishan’s age is 14 years.

Answer : 50 years
Explanation :
Let the father’s present age be X years
Father’s age 15 years ago = (X - 15) years
Gautam’s present age = 20% of (X - 15)
(X - 15) / 5 years
Gaurav’s present = 60% of (X – 10)
3(X – 10) / 5 years
(X – 15) / 5 + 3(X – 10) / 5 = 31
⇒ x – 15 + 3x – 30 = 155
⇒ x = 50

Answer : 70 years
Explanation :
Let Vidyut’s present age be "x" years and Tiger’s present age be "y" years.
Then, according to the first condition,
X−10 = 3(y−10) => x−3y = −20…..........(1)
Now, Vidyut’s age after 10 years = (x+10)(x+10) years.
Tiger’s age after 10 years = (y+10)(y+10) years.
(x+10) = 2(y+10) => x−2y = 10......(2)
Solving (1) and (2),
we get x = 70 and y = 30
Vidyut’s present age = 70 years and Tiger’s present age = 30 years.

Answer : 9,50
Let the age of Salman = A, Cousin = B and Salim = C
From given, A=3B
4 years ago, A+4=31
⇒A=27
sub in above B , we get B = 9
C=2(27−4)+4=46+4=50
Hence Cousin = 9 years and Salim = 50 years.

Answer : 42
Explanation:
Let the present age of Akshay and Bani be 4x and 5x respectively.
Ten years ago, Akshay was one fourth of Bani in age
=> 4(4x – 10) = (5x – 10)
=> 6x – 20 = 4x – 10
=> 11x = 50
=> x = 5
Total of their present ages = 4*5 + 5*5 = 42