DXC Quants Problems on Ages Quiz 1

Answer : 32 years
Explanation :
The ratio of the present age of Pawan and Kirti = 2 : 3 (2x, 3x)
Swati = 3 + Kirti = 3x + 3
Average age of three of them = 25 years
So, sum of the present ages of three of them = 75 years
A/c to the question
2x + 3x + 3x + 3 = 75
8x = 72
x = 9
Present age of Pawan = 2x = 18 years
Present age of Johnny = 2*Pawan = 2*18 = 36 years
Therefore age of Johnny, 4 years ago = 32 years

Answer : 28 years
Solution:
The ratio of age of Rashmi’s age after 2 years and Meena’s present age
= 2 : 1 (2x, x)
Pankhuri’s present age = 23 years
Meena’s present age = 23 – 8 = 15
x = 15
2x = 30
After 2 years, the age of Rashmi = 30 years
The present age of Rashmi = 28 years

Answer : 23 years
Explanation :
Let 5 years hence the age of daughter and son be 7x years and 6x years respectively, then
Present age of daughter= (7x - 5) years
Present age of son = (6x - 5)years
⇒ Present age of Prakash = [(7x - 5) + (6x - 5) + 8] = (13x - 2)years
∴ Present age of Prakash's wife = [(13x - 2) + 7] = (13x + 5) years
Given, present age of Prakash's wife is thrice the present age of his son.
(13x + 5) = 3(6x - 5)
⇒ x = 4
Hence, his daughter’s present age = (7x - 5) = 23 years.

Answer : 11.8
Explanation:
Given, Total average ages of 60 boys is 12
Therefore, the total age of 60 boys = 12 x 60 = 720 years.
Given, average ages of 20 boys is 13
Therefore, total ages of 20 girls = 20*13 = 260 years
Given, average ages of 15 boys is 11
Therefore, total ages of 15 boys = 15*11 = 165 years
Then, average age of leftover boys will be,
720 – (260+165)/ 60 – (20+15)
= 295/25 = 11.8 years

Answer : 18
Explanation:
Given, Naina’s present age is 18 years
Given, product of their ages is 648
Then, Kamran’s age will be 648/18 = 36 years.
The sun of Naina and Kamran’s age is 36+18 = 54
On dividing 54 by 3, we get 18.

Explanation:
Let Radhika’s father’s current age be x
Then, the Radhika’s present age is 4/7x
Given, 4/7x + 7 = 2/7 (x + 7)
x = 24.5

Answer : 5 years
Explanation :
The ratio of age of Kavya, 4 years ago, and the present age of Lakshmant = 2: 1 (2x, x)
Muntashir = Lakshit + 12
Muntashir = Kavya – 10
Kavya – 10 = Lakshman + 12
2x + 4 – 10 = x + 12
x = 18
Present age of Kavya = 2x + 4 = 40 years
The present age of Lakshman = 18 years
Present age of Muntashir = 18 + 12 = 30 years
The present age of Muntashir = 6* Present age of Nishi
Present age of Nishi = 30/6 = 5 years

Answer: 20 , 30 and 30 years
Let the present age of three engineers be : 4x, 6x and 8x
(3x – 5) + (5x – 5) + (7x – 5) = 65.
18x – 15 = 75 ⇒ 18x = 90 ⇒ x = 5.
Their present ages are 20 years, 30 years and 40 years respectively.

Answer: 38 years
Let the ages of Akshay, Neil and Sunil 5 years ago be 2x, 3x and 4x years respectively.
So, total of their present ages will be,
(3x + 5) + (4x +5) + (4x + 5) = 106
11x + 15 = 106
11x = 88
x = 8.
So, the present age of Sunil = 4x + 6 = 4 × 8 + 6 = 38 years.

Answer : 15 years
Solution:
The ratio of Heeralal’s age six years hence to Radhika’s present age = 5 : 3 (5x, 3x)
Present ages of Heeralal to Radhika = 5x – 6: 3x
Present ages of Prakash to Radhika = 2 : 1 (2x, x)
Present ages of Prakash, Heeralal and Radhika = 6x, 5x – 6, 3x
Heeralal = Prakash – 11
Prakash – Heeralal = 11
6x – (5x – 6) = 11
6x – 5x + 6 = 11
x = 5
Heeralal’s age, 4 years ago = 5x – 6 – 4 = 25 – 10 = 15 years