Table Chart Questions and Answers Quiz-2

Total no. Of people - 124

No of Indians in (15-20yrs) - 7

No. Of Indians in (21-30)yrs - 16

No. Of Indians in (31+)yrs – 15

Percentage of people who love Indian food= 38/124*100 = 30.64%

Hence Option C is the correct one.

Total number of people = people from age (15-20) + people from age (21-30) + people from age 31+) = 33 + 31+ 58= 122

Percentage of total sample aged between (15-20) = = 27.0491

The nearest whole percentage will be= 28

Hence Option C is the correct one.

It is evident by looking at the table that Delhi has the highest increase in population. (500-240)= 260

Hence option A is the correct one.

Total production during the period= 6560

Total wheat during the period= 15864

Therefore % wheat production over total production=

6560/15864 x 100 =41.35

Hence Option D is the correct one.

% increase in wheat production in 2002-03 over 2001-02

= 1720-1360= 360 million tonnes

Therefore % increase=

Hence Option B is the correct one

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Solution:

Number of students who passed half-yearly exams in the school

= (Number of students passed in half-yearly but failed in annual exams) + (Number of students passed in both exams)

= (6 + 17 + 9 + 15) + (64 + 55 + 46 + 76) = 288.

Also, the Number of students who passed annual exams in the school

= (Number of students who failed in half-yearly but passed in annual exams) + (Number of students passed in both exams)

= (14 + 12 + 8 + 13) + (64 + 55 + 46 + 76) = 288.

Since, the number of students passed in half-yearly = the number of students passed in annual exams. Therefore, it can be inferred that both the examinations had almost the same difficulty level. Thus Statements (a), (b), and (d) are false and Statement (c) is true.

 

Solution:

Since the classification of the students on the basis of their results and sections form independent groups, so the total number of students in the class:

= (28 + 23 + 17 + 27 + 14 + 12 + 8 + 13 + 6 + 17 + 9 + 15 + 64 + 55 + 46 + 76)

= 430.

Solution:Pass percentages in at least one of the two examinations for different sections are:

For Section A = \frac{14+6+64}{28+14+6+64} = \frac{84}{112}\times 100 \% = 75\%

For Section B = \frac{12+17+55}{23+12+17+55}\times 100 \% = 78.5\%

For Section C = \frac{8+9+46}{17+8+9+46}\times 100 \% = 78.75\%

For Section D = \frac{13+15+76}{27+13+15+76}\times 100\% = 79.39\%

Clearly, the pass percentage is maximum for Section D

Solution:

Total number of students passed in annual exams in a section

= [ (No. of students failed in half-yearly but passed in annual exams) + (No. of students passed in both exams) ] in that section

The success rate in annual exams in

Section A = \frac{14+64}{112}\times 100\% = 69.64\%

Similarly, the success rate in annual exams in:

Section B = \frac{12+55}}{107}\times 100\% =  62.62\%

Section C = \frac{8+46}{80}\times 100\% = 67.5\%

Section D = \frac{89}{131}\times 100\% = 67.94\%

Clearly, the success rate in the annual examination is maximum for Section A.