Question 1
73.52%
75%
74.56%
78.46%
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% of Liquid in Solution A = 25% ⇒ % of Water in Solution A = 75% Volume of Solution A = 24 Litres ⇒ Volume of Water in Solution A = (75/100) × 24 = 18 Litres % of Liquid in Solution B = 30% ⇒ % of Water in Solution A = 70% Volume of Solution B = 10 Litres ⇒ Volume of Water in Solution B = (70/100) × 10 = 7 Litres If Solution A is mixed with Solution B ⇒ Net Total Volume of Solution = (24 + 10) = 34 Ltrs ⇒ Net Total Volume of Water in Solution = (18+ 7) = 25Ltrs % of Water in New Mixture = (Volume of Water in New Mixture / Volume of New Mixture) × 100 % of Water in New Mixture = (25 /34) × 100 = 73.52%
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Question 2
24
20
18
25
None of these
let pure milk= x litr. total mixture=x+4 3x*120/100=(x+4)3 6x5x=20 x=20
Question 3
29.35%
28. 57%
24. 57%
27. 75%
26. 57%
ratio of water and milk remain same after sold of 40 ltr i.e 28/72 now remaining quantity is 16540= 125 amount of water in 125 ltr is 125of 28%=35 ltr amount of milk in 125 ltr= 12535=90 now a/c to question 35+13/90+30=48/120 water amount is 48 ltr in total amount 125+30+13=168 hence the % of water is 48*100/168=28.57%
Question 4
6:5
8:7
3:7
6:1
C.P of 1 Kg C.P of 1 Kg rice of 1st rice of 2nd kind (930p) kind (1080p) \\\\ / Mean Price (1000p) / \\\\ (1080 – 1000) : (1000  930) 80 70 Thus, required ratio = 80 : 70 = 8 : 7
Question 5
3 : 4
2 : 3
3 : 2
4 : 3
C.P of a unit quantity of 1st kind = Rs. 3.20 C.P of a unit quantity of 2nd kind = Rs. 2.90 Mean price = Rs.3.08 C.P of unit quantity C.P of unit quantity of 1st kind of 2nd kind (Rs. 3.20) (Rs. 2.90) \\\\ / Mean Price (Rs.3.08) / \\\\ (3.08 – 2.90) : (3.20 – 3.08) 0.18 0.12 Required ratio = 0.18 : 0.12 = 3 : 2
Question 6
8 : 3
7 : 5
Milk in 1 litre mixture of A = 4/7 litre. Milk in 1 litre mixture of B = 2/5 litre. Milk in 1 litre mixture of C = 1/2 litre. By rule of alligation we have required ratio X:Y X : Y 4/7 2/5 \\ / (Mean ratio) (1/2) / \\ (1/2 – 2/5) : (4/7 – 1/2) 1/10 1/1 4 So Required ratio = X : Y = 1/10 : 1/14 = 7:5
Question 7
1 : 7
2 : 9
7 : 9
3 : 8
Spirit in 1 litre mix of A = 5/7 litre. Spirit in 1 litre mix of B = 7/13 litre. Spirit in 1 litre mix of C = 8/13 litre. By rule of alligation we have required ratio X:Y X : Y 5/7 7/13 \\\\\\\\ / (8/13) / \\\\\\\\ (1/13) : (9/91) 7 9 Therefore required ratio = 1/13 : 9/91 = 7:9
Question 8
Rs. 12.47
Rs. 10.80
Rs. 15.17
Rs. 47.66
Let the rate of second quality be Rs x per Kg. C.P of 1Kg wheat of 1st kind = 930p C.P of 1 Kg wheat of 2nd kind = 100x p Mean price = 1000p By rule of alligation we have required ratio 8 : 7 930 x \\\\\\\\ / (Mean Price) (10) / \\\\\\\\ x10 : 0.7 :: 8 : 7 So we get required ratio, (x10) : 0.7 :: 8 : 7 ⇒ x = 10.80 per Kg
Question 9
10 liters
20 liters
30 liters
40 liters
Number of liters of water in 125 liters of the mixture = 20% of 150 = 1/5 of 150 = 30 liters Let us Assume that another \'P\' liters of water are added to the mixture to make water 25% of the new mixture. So, the total amount of water becomes (30 + P) and the total volume of the mixture becomes (150 + P) Thus, (30 + P) = 25% of (150 + P) Solving, we get P = 10 liters
Question 10
83.33 ml
90.90 ml
99.09 ml
can't be determined
Profit (%) = 9.09 % = 1/11 Since the ratio of water and milk is 1 : 11, Therefore the ratio of water is to mixture = 1:12 Thus the quantity of water in mixture of 1 liter = 1000 x (1/12) = 83.33 ml
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November 18, 2020