TCS Data Types Quiz-1

Question 1

Time: 00:00:00
Neelam wants to share her code with a colleague, who may modify it. Thus she wants to include the date of the program creation, the author and other she wants to include the date of the program creation, the author and other information with the program. What component should she use?

header files

header files

Iteration

Iteration

pre proccessor

pre proccessor

Comments

Comments

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Obviously answer is \"comments\" only

why?

preprocessor directive

c

header files

header files

comments

no

The answer is header files

header files

header files

header files

pre processor

Comments in the codes are used to explain what is happening in the code. It is helpful as if one coder writes code he also writes comments so that other developers can understand easily about the coding logic.

comments

Sir how the ans came

header file is the correct answer as we can use the #include header file

comments

comments

comment

Preprocessor

header files

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Question 2

Time: 00:00:00
What is the output of the following code statements? The compiler saves the first integer at the memory location 4165 and the rest at consecutive memory spaces in order of declaration. Integer is one byte long.
integer a
pointer c, d
a = 30c = &a
c = &a
d = c
a = a + 10
print *c

30

30

40

40

4165

4165

4166

4166

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*c points to the value of a; so given a=30 output is 40. Had it been to print only c then the output would have been the address of a that is 4165

check the pic

A is assigned as 30 initially Then C contain the adress of A Then d stores c which means value at the adress which c holds that means 30.. Then a is updated and become 40.. Hence when *C is printed then value at A is printed..

Actually *c=*(&a) a=30+10 a=40 There fore a=40

int a; *c, *d; a = 30; c = &a; //pointer c has the memory location of a i.e 4165 d = c ; //d is 4165 a = a +10; print *c //*c is a defererence pointer which gives the value of the variable to which it is pointing at, so 40 is the answer

output is 40

#include int main() { int a; int *c, *d; a=30; c = &a; d=c; a=a+10; printf(\"%d\",c); } o/p: 4165 i.e is the address of c but is we print ----- printf(\"%d\",*c); then o/p is : 40

As c is assigned with address of a,a is updated , so when we print c, updated value of a will be printed. a=30 c=&a a=a+10 /a=40----> c=30 print(*c)

4165

40

4165

a=30; c=&a; so c=4165; d=4165; c=4165

4165

why?

why?

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Question 3

Time: 00:00:00
A data type is stored as a 6 bit signed integer. Which of the following cannot be represented by this data type?

-12

-12

32

32

18

18

6

6

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-12 , in question they mention signed integer

i think -12

-12

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Question 4

Time: 00:00:00
A language has 28 different letters in total. Each word in the language iscomposed of maximum 7 letters. You want to create a data-type to store a word ofthis language. You decide to store the word as an array of letters. How many bits will you assign to the data-type to be able to store all kinds of words of the language.

7

7

28

28

72

72

196

196

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how it can be 35. someone pls explain

In binary, there are only two possibilities- zero and one.  Thus, looking at the powers of 2, we realize that 32 is the closest exponential result of 2 to 28, where 2^5 = 32. Hence, to cover all the possibilities, we need 5 bits at the least. But there are seven letters. Thus, the number of bits we require is 7 * 5 = 35 bits  Read more on Brainly.in - https://brainly.in/question/3672631#readmore

35

196

didn\'t understand please explain anyone

196

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Question 5

Time: 00:00:00
A 10-bit unsigned integer has the following range:

0 to 1000

0 to 1000

0 to 1024

0 to 1024

0 to 1023

0 to 1023

0 to 1025

0 to 1025

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0 to 1023

0 to 1023

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Question 6

Time: 00:00:00
Parul takes as input two numbers: a and b. a and b can take integer valuesbetween 0 and 255. She stores a, b and c as 1-byte data type. She writes the following code statement to process a and b and put the result in c.
c = a + 2*b
To her surprise her program gives the right output with some input values of a and b, while gives an erroneous answer for others. For which of the following inputs will it give a wrong answer?

a = 200 b = 10

a = 200 b = 10

a = 10 b = 200

a = 10 b = 200

a = 100 b = 50

a = 100 b = 50

a = 50 b = 100

a = 50 b = 100

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option B gives wring output for given range

Option A

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Question 7

Time: 00:00:00
Which is used to convert source code to target language

Linker

Linker

Loader

Loader

Executer

Executer

Compiler

Compiler

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compiler

compiler

D

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Question 8

Time: 00:00:00
Tricha wants to store a list of binary data.Which of following data types should she use?

Integer

Integer

Float

Float

Character

Character

Boolean

Boolean

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binary data means either 0 or 1 boolean value are 0\'s and 1\'s so answer boolean

D

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Question 9

Time: 00:00:00
Which of the following options is an exception to being a part of composite data types?

Arrays

Arrays

Structure

Structure

Union

Union

Stacks

Stacks

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stack

Union

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Question 10

Time: 00:00:00
Which data type is most suitable for storing a number 65000 in a 32-bit system?

short

short

int

int

long

long

double

double

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Long

65000 comes in the range of short (16-bit) which occupies the least memory. Signed short ranges from -32768 to 32767 and hence we should use unsigned short.

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["0","40","60","80","100"]
["Need more practice! \r\n \r\n \r\n","Keep trying! \r\n \r\n \r\n","Not bad! \r\n \r\n \r\n","Good work! \r\n \r\n \r\n","Perfect! \r\n \r\n \r\n"]

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