TCS Divisibility Quiz-1 Questions and Answers

Question 1

Time: 00:00:00
If a positive integer n is divided by 5, the remainder is 3. Which of the numbers below yields a remainder of 0 when it is divided by 5?

 

n + 3

n + 3

n + 2

n + 2

n - 1

n - 1

n - 2

n - 2

n + 1

n + 1

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b

n+2

n divided by 5 gives 3 as remainder, that means the n could be 8, 13, 18, 23 and so on................. purely divisible by 5 are nos ends with 0, 5. So, if we check it for each case for from (A) ends with 0 or 5 we get 8+2=10 divisible by 5.

D

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Question 2

Time: 00:00:00
If an integer n is divisible by 3, 5 and 12, what is the next larger integer divisible by all these numbers?

 

 

n + 3

n + 3

n + 5

n + 5

n + 12

n + 12

n + 60

n + 60

n + 15

n + 15

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LCM of 3, 5, 12 is 60 (3, 5, 3, 4) = (3, 5, 4) = 60 Divisibility by 5 number should have 0, 5 at last. Divisibility by 12 number should divisible by (3, 4) or even digit at last. n+60 = ______0 then we left with C and D, 60+60=120 divisible by 3, 5, 12

Since it is already mentioned in the question that \'n\' is divisible by 3,5&12... So, if we take (n+3)/5 or 12 yields n/5 + 3/5 or n/12 + 3/4 , but 3 is neither divisible by 5 nor 12 .. Only number divisible by 3,5,12 is 60.. Therefore only ( n+60 ) / 5,3or12.. yields remainder as 0

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Question 3

Time: 00:00:00
Which of these numbers is not divisible by 3?

 

 

339

339

342

342

552

552

1111

1111

672

672

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D

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Question 4

Time: 00:00:00
What is the smallest positive 2-digit whole number divisible by 3 and such that the sum of its digits is 9?

 

18

18

27

27

72

72

90

90

33

33

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18=1+8=9 9/3=3 answer =18

Yo u can easily find answer with the help of given options 18 =1+8=9 18 is also divisible by 3

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Question 5

Time: 00:00:00
If n is an integer, when (2n + 2)² is divided by 4 the remainder is

 

zero

zero

1

1

2

2

3

3

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It is (2n+2)^2

answer is d

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Question 6

Time: 00:00:00
Let N = 80pq2pq (7digit number). If N is exactly divisible by 120 then the sum of the digits in N is equal to:

27

27

33

33

72

72

18

18

90

90

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Question 7

Time: 00:00:00
If 53p26p3 is a 7 digit number divisible by 9 and if 757qp is divisible by 8 then the minimum value of p + q is:

 

4

4

8

8

12

12

16

16

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a

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Question 8

Time: 00:00:00
Find the remainder when 1201 × 1203 ×1205 × 1207 is divided by 6.

5

5

3

3

9

9

6

6

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Question 9

Time: 00:00:00
Find the remainder when 1! + 2! + 3! + 4! + 5! + .......100! is divided by 24.

5

5

9

9

7

7

11

11

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Question 10

Time: 00:00:00
123456789101112.... . 434445 . Find the remainder when divided by 45?

zero

zero

5

5

3

3

1

1

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["0","40","60","80","100"]
["Need more practice! \r\n","Keep trying! \r\n","Not bad! \r\n","Good work! \r\n","Perfect! \r\n"]

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