Hexaware Attention to Details Quiz 1

Ans: The correct equation is : 125 / 25 - 20 + 15
According to BODMAS, we will divide first , therefore the answer is 5 - 20 + 15 = 0

The numbers between A and Z are : 4 , 3 , 5 , 1 , 2 , 0
Sum = 4 + 3 + 5 + 1 + 2 + 0 = 15
Twice the sum = 2 * 15 = 30

Ans: We can see from the table that the first and the third columns are alike, therefore, E will be the answer.

Ans: 64 A 36 D 6 B 18 A (7 C 13) => 64 + 36 / 6 - 18 + ( 7 * 13 ) = 64 + 6 - 18 + 91 = 143

Ans:

Step 1: Since D and R are common in all the words, we will move to the third letter. The third letters are A, O, A, I, A
We know that DROUGHT will be the last word and DRIBBLE will be the fourth word.

Step 2: Since the third letter is common in the three remaining words, we will move to the fourth letter. The fourth letters are U, W, S.
The first word will be DRASTIC.
The second word will be DRAUGHTSMAN.
The third word will be DRAWING.
The fourth word will be DRIBBLE.
The fifth word will be DROUGHT.

The order is: 51342

Ans:
L & M => L is neither greater than nor equal to M => L is less than M => L<M
M $ N => M is not smaller than N => M is greater than or equal to N => M>=N
N # O => N is neither greater than nor smaller than O => N is equal to O => N=O

Therefore, we can conclude that L < M >= N = O.

Our conclusions are

• N # L => N is equal to L (False)


• M $ O => L is greater than or equal to O (True)

Ans:
S ( T => S is neither smaller than nor equal to T => S is greater than T => S > T
T * Q => T is not greater than Q => T is less than or equal to Q => T<=Q
Q & Z => Q is neither greater than nor equal to Z => Q is less than Z => Q < Z

Therefore, we can conclude that S > T < = Q < Z
Our conclusions are
Z # Q => Z is greater than Q (True)
S,Q ( T => S and Q are both greater than T (True)

Therefore, Both conclusions I and II are true.

Ans:
Y $ U => Y is not smaller than R => Y is greater than or equal to U => Y > = U
U * V => U is not greater than V => U is smaller than or equal to V => U <=V.

Therefore, we can conclude that Y >= U <= V
Our conclusions are
U & V => U is smaller than V (True)
U ( Y => U is greater than Y (False)

Therefore, Only conclusion I is true.

Ans:
A # B => A is neither greater than nor smaller than B => A is equal to B => A = B
B $ C => B is not smaller than C => B is greater than or equal to C => B <= C
C ( D => C is neither smaller nor equal to D => C is greater than D => C>D

Therefore, we can conclude that A = B <= C > D
Our conclusions are
A # D => A is equal to D (False)
A # D => B is equal to D (False)

Therefore, Neither conclusion I nor II is true.

Ans:
F * G => F is not greater than G => F is smaller than or equal to G => F <=G.
G # H => G is neither greater than nor smaller than H => G is equal to H => G = H
H ( R => H is neither smaller nor equal to R => H is greater than R => H > R

Therefore, we can conclude that F <= G = H > R
Our conclusions are
F * H => F is smaller than or equal to H (True)
R ( G => R is greater than G (True)

Therefore, Both conclusions I and II are true..