Quiz-1

Let the daughter's age be x and rabindranath age is 4x.
So as per question, 4x + 5 = 3(x + 5). So x = 10.
Hence the present age of the daughter is 10 years and the present age of fath rabindranath is 40 years.
So after 5 + 5 = 10 years, daughter age would be 20 years and rabindranath’s age would be 50 years.
Hence rabindranath would be 50/20 = 2.5 times of daughter’s age.

Let Giani's present age be x
Giani's age before 10 years = x - 10)
Giani's age after 20 years = (x + 20)
We are given that, Giani's age after 20 years (x + 20) is 10 times his age 10 years back (x – 10)
Therefore, (x + 20) = 10 (x – 10)
Solving the equation, we get x + 20 = 10x – 100
9x = 120, x = 13.3 years

Let the age of Ranveer be y
Aalaya is 15 years elder than Ranveer = (y + 15).

So Aalaya's age 5 years ago = (y + 15 – 5).
Ranveer's age before 5 years = (y – 5)
5 years ago, Aalaya is 3 times as old as Ranveer
(y + 15 – 5) = 3 (y – 5)
(y + 10) = (3y – 15)
2y = 25 ⇒ y = 12.5
Ranveer's age = 12.5 years
Aalaya's age = (y + 15) = (12.5 + 15) = 27.5 years.

We are given that age ratio of Anil:Mukesh = 2: 3
Honey’s age = 2x and Mukesh’s age = 3x
One year ago, their age was 2x and 3x.
Hence at present, Anil's age = 2x +1 and Mukesh's age = 3x +1
After 5 years, Honey’s age = (2x +1) + 5 = (2x + 6)
Mukesh's age = (3x +1) + 5 = (3x + 6)
After 5 years, this ratio becomes 4: 5. Therefore,
(2x+6) / (3x+6) = 4/5
10x + 30 = 12x + 24 ⇒ x = 3
Mukesh's present age = (3x + 1) = (3x 3 + 1) = 10 years
Anil's present age = (2x + 1) = (2x 3 + 1) = 7 years

10 years ago, the age of Kareena Kapoor was three times the age of her son(Taimur).

Say, the age of son was x and Kareena's age was 3x.
At present: Kareena's age is (3x + 10) and son’s age is (x + 10)
After ten years: Kareena's age will be (3x + 10) +10 and son’s(Taimur) age will be (x + 10) + 10.

Given that, Kareena's age is twice that of Taimur(his son) after ten years.
(3x + 10) +10 = 2 [(x + 10) + 10]
(3x + 20) = 2[x + 20]
Solving the equation, we get x = 20
(3x + 10): (x + 10) = 70: 30 = 7: 3.

Let us assume x years ago
At present: Kehmu is 50 years and Saif is 40 years
x years ago: Kehmu’s age = (50 – x) and Saif's age = (40 – x)
Given, the ratio of their ages was 3:2
(50-x) / (40-x) = 3/2
Solving, we get: x = 20
Therefore, the answer is 20 years.

Their present ages be 4X and 5X.
5 years ago, the ratio of their ages was 7:9, then (4X - 5) :( 5X - 5) = 7:9
X = 45 - 35 ⇒ X = 10.
Their present ages are: 40, 50.

Present age of the son be P, he was born P years ago.
The age of the man was: (48 - P).
His age when the son was born should be equal to 1/3 of P.
(48 - P) =1/3 P ⇒ P = 36

Let Roshan's age be x years.
Then, Dinesh 's age = (x - 9) years.
(x - 9)/x = 4/5
x = 45 Hence, Dinesh's age = (x - 9) = 36 years.

Currently, the ratio of their ages is 5: 3.

Suppose, their ages are: 5x and 3x.
Motu’s age 4 years ago = 5x – 4
Patlu’s age after 4 years = 3x + 4
Ratio of Motu’s age 4 years ago and Patlu's age after 4 years is 1 : 1
Therefore,
(5x - 4) / (3x + 4) = 1/1
Solving, we get x = 4
We are required to find the ratio between Motu’s age 4 years hence and Patlu’s age 4 years ago.
Motu's age: (5x + 4)
Patlu's age: (3x – 4)
Putting the value of x, we get:
(5x + 4) / (3x - 4) = 3/1 = 3:1