Capgemini Geometry & Trigonometry Questions and Answers Quiz-1

Question 1

Time: 00:00:00
An oblong piece of ground measures 19m 2.5 dm by 12m5dm. From center of each side of the ground, a path 2m wide goes across to the center of the opposite side. What is the area of the path?

34 m2

34 m2

43 m2

43 m2

54 m2

54 m2

59.5 m²

59.5 m²

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Question 2

Time: 00:00:00
In triangle PQR, PQ=6 cm, PR=8 cm, and QR=12 cm. Calculate the area of the triangle PQR

23.33 cm^{2}

23.33 cm^{2}

17.5 cm^{2}

17.5 cm^{2}

21.33 cm^{2}

21.33 cm^{2}

28.67 cm^{2}

28.67 cm^{2}

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Question 3

Time: 00:00:00
If the perimeter and the diagonal of a rectangle is 18 cm and √41 cm respectively. Calculate the area of the rectangular field.

25 cm^{2}

25 cm^{2}

20 cm^{2}

20 cm^{2}

29 cm^{2}

29 cm^{2}

18 cm^{2}

18 cm^{2}

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Question 4

Time: 00:00:00
Find the area of Rhombus one of whose diagonals measures 8 cm and the other 10 cm.

40 cm2

40 cm2

41 cm2

41 cm2

44 cm2

44 cm2

42 cm2

42 cm2

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Question 5

Time: 00:00:00
Which of the following graph indicates the graph of {(sin t, cos t):- π/2\leq t\leq 0} in xy-plane?

 
Cocubes previous year papers

A

A

C

C

D

D

B

B

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Question 6

Time: 00:00:00
A rectangular grassy plot is 112 m by 78 m. It has a gravel path 2.5 m wide all round it on the inside. Find the area of the path and the cost of constructing it at Rs. 2 per square metre?

930m^{2}, 1850 Rs

930m^{2}, 1850 Rs

927m^{2}, 1800 Rs

927m^{2}, 1800 Rs

925m^{2}, 1850 Rs

925m^{2}, 1850 Rs

932m^{2}, 1860 Rs

932m^{2}, 1860 Rs

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Question 7

Time: 00:00:00
What is the radius of the circular plate of thickness 1cm made by melting a sphere of radius 3cm?

6cm

6cm

7cm

7cm

4cm

4cm

5cm

5cm

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Question 8

Time: 00:00:00
A polygon has 77 diagonals.Determine the number of sides?

18

18

16

16

14

14

15

15

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No. of diagonals given = 77 no. of sides of the polygon can be determined by the formula, diagonal = n*(n-3)/2 from the given data we have, 77 = n*(n-3)/2 77*2 = n*(n-3) 154 = n^2 - 3n 0 = n^2 - 3n - 154 0 = n^2 -14n + 11n - 154 0 = n(n-14) +11(n-14) 0 = (n+11) and (n-14) here, n+11, n = -11 (not possible) where as n-14, n = 14 (answer)

(N(N-3))/2=Y where Y = no. of diagonals and N = no. of sides so, (14*11)/2=154/2=77.

d=s(s-3)/2 where d= no of diagonals s=no of sides

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Question 9

Time: 00:00:00
A square field of area 31684 m^{2} is to be enclosed with the wire placed at height 1 m, 2 m, 3 m, 4 m above the ground. What length of the wire will be required if its length required for each circuit is 5% greater than the perimeter of the field?

2990.5m

2990.5m

2990.2m

2990.2m

2990.4m

2990.4m

2990.3m

2990.3m

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Question 10

Time: 00:00:00
Determine the metal required to make a 21 m long pipe if its inner and outer diameter is 12 m and 10 m respectively

728 m^{3}

728 m^{3}

727 m^{3}

727 m^{3}

726 m^{3}

726 m^{3}

729 m^{3}

729 m^{3}

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