Hexaware Probability Quiz 1

Sample space = {H,T}

probability of getting tail  = \frac{1}{2}

probability of getting green balls = \frac{2}{9}

No of black = 26

probability of getting black card = \frac{26}{52} = \frac{1}{2}

Sample Space = {1,2,3,4,5,6}

Prime numbers = {2 ,3 ,5}

Probability of getting green balls = \frac{3}{6} = \frac{1}{2}

P(A ∪ B) = P(A) + P(B) - P(A∩B)

=> P(A ∪ B) = 0.3 +0.2 -0.1 = 0.4

Value of Probability lies between 0 and 1

Multiple of 5 between 1 and 26 which is 2 - digit number = {10,15,20,25}

Sample space = 16

Required Probability = \frac{4}{16} = \frac{1}{4}

Either an orange or green = 3 + 5 = 8

probability of having either an orange or a green bulb = \frac{8}{5+3+2} = \frac{8}{10} =0.8

Number of girls = 16

Probability that the one called is a girl = \frac{16}{12+16} = \frac{16}{28} =\frac{4}{7}

Out of 6 occurrences there is only one possibility of getting ‘2’ as on the dice

So the required probability will be \frac{1}{6}