TCS Tabular DI Quiz-1

Social Welfare outlay for 1991-92 = 2073
Social Welfare outlay for 1992-93 = 3918
Therefore,
Percentage Increase =(\frac{3918-2073}{2073})*100\simeq 89.00%

Production of E in 2004 = 130
Production of B in 2003 = 210
Therefore,
Required Percentage = (\frac{130}{210}*100 )=61.9%

Hence, option D is correct.

The pass percentages in at least one of the two semesters for the four departments are  :

For Department A,

[\frac{(14+6+64)}{(28+14+6+64)}]*100=75%

For Department B,

[\frac{(12+17+55)}{(23+12+17+55)}]*100=78.50%

For Department C,

[\frac{(8+9+46)}{(17+8+9+46)}]*100=78.50%

For Department D,

[\frac{(13+15+76)}{(27+13+15+76)}]*100=79.39%

Therefore, the pass percentage is minimum for Department A.

No. of children in area A = 22% of 36000 = 7920
No. of children in area C = (100 - 24 - 52)% of 72000 = 17280
No. of children in area E = 42% of 86000 = 36120
No. of children in area F = (100 - 44 - 25)% of 94000 = 29140
Therefore ,
Average no. of children = 22615 .

Total no. of bikes sold by stores T and U together in May = 616
Total no. of bikes sold by stores P and R together in March = 504

Therefore,
Required Ratio = 616 : 504
= 11 : 9

Required Percentage = (\frac{164}{821}*100)\simeq 21%

Maximum temperature of City C on 1st November = 4
Minimum temperature of City A on 1st January = -7

Therefore,
Required Difference = 4 - (-7)
= 11

It is clear from the given table that on 1st October , the temperature of City D is second highest and on 1st November, temperature of City B is the highest .

Let, total sales of all brands in 2010 be 100.
So, total sales of all brands in 2012 = 200% of 100 = 200

For brand A in 2010:
Profit = 30 × 8000 × 20% = Rs. 48,000

Similarly ,
Profit for brand B = Rs. 16,250

Profit for brand C = Rs. 37,500

Profit for brand D = Rs.39,375

Therefore,
Total profit = 48000 + 16250 + 37500 + 39375
= Rs. 1,41,125

Hence, option D is correct.

For Country S,
Population above poverty line = (100 - 19)% of 70 M
= 56.7 M

Now,
No. of females above poverty line = (\frac{3}{7}*56.7)=24.3 M