Once you attempt the question then PrepInsta explanation will be displayed.
raju+vicky+tinku one day work =\left ( \frac{1}{10} \right )+\left ( \frac{1}{12} \right )+\left ( \frac{1}{15} \right )=\left ( \frac{1}{4} \right )
now for 2 days together work done= 2*(1/4)= 1/2
......now work done by tinku in last 3 days alone=(3/15)=(1/5)
remaining work= 1-(1/2 + 1/5)= 3/10
....now vicky+tinku one day work=(1/12)+(1/15)=9/60
therefore 3/10 work will be done by both of them in= \left ( \frac{60}{9} \right )\times \left ( \frac{3}{10} \right )= 2 days
now answer=
2days(as got from above; it is days required to do rem. work)+ 3days(when vicky leaves)+2days(raju leaves)=7 days ans.
Video solution:
src="https://www.youtube.com/embed/Uy-L_Vh_hdo"
frameborder="0" allowfullscreen="" style="position: absolute; top:0; left: 0">
Login/Signup to comment