InfyTQ Aptitude Previous Year Questions and Answers PDF

Option(B) is correct

Total sum of cars in 58 country =(60*40)−(25+30)

=2400−55

=2345

Average =(2345 / 58)

= 40.4

Option(d) is correct

|Y| can take 9 values.

To get |Y|<3 ( i.e., −3<X<+3) take Y={-2, −1, 0, 1, 2}

⇒ P(|Y|<3)= Favourable Cases / Total Cases

= 5/9

Number of ways of selecting 3 consonants from 7

^{7}\textrm{C}_{3}

Number of ways of selecting 2 vowels from 4

^{4}\textrm{C}_{2}

Number of ways of selecting 3 consonants from 7 and 2 vowels from 4

= ^{7}\textrm{C}_{3} \times ^{4}\textrm{C}_{2}

\frac{7\times 6 \times 5}{3 \times 2} \times \frac{4 \times 3}{2 \times 1}

= 210

It means we can have 210 groups where each group contains a total of 5 letters (3 consonants and 2 vowels).

Number of ways of arranging 5 letters among themselves

5! = 5*4*3*2*1

= 120

Hence, the required number of ways

210 * 120 = 25200

The ratio of the cost of the table and the chair would be (40-25) : (25 - 20) or 3 : 1 as can be seen from the following allegation figure:

20% profit on table                    Average profit 25%                40% profit on chair

Cost price Ratio = 3 : 1

Thus the cost of the table would be Rs 1500

Otherside = \sqrt{8^{2}-5^{2}}=\sqrt{39} = 6.244m

Therefore the area = l x b = 8 x 6.244 = 49.95m^{2} which is approximately equal to 50m^{2}

Solution

Percentage of students passed to class X = 100 % - 15 % = 85 %

85 % of 55

= 85/100 × 55

= 4675/100

= 46.75

= 47

Therefore, 47 students passed to class X.

\frac{25}{75}\times \frac{3}{4}\times \frac{51}{102}\times \frac{324}{81} = \frac{1}{2}

1:2

Option(B) is correct

Explanation:

Let total distance =𝐷

Distance travelled at 4 kmph speed =(2/3) 𝐷

Distance travelled at 5 kmph speed =(1 − 2/3 )𝐷 = (1/3) 𝐷

Total time =1 hr 24 min = (60+24) min =8460 hr = 21/15 hr

We know,

Time=    Distance / Speed

Total time

21/15 = 2/34𝐷 + 1/35𝐷

21/15 =2𝐷/12 + 𝐷/15

84=14𝐷

𝐷=6 𝐤𝐦