InfyTQ Time and Distance Quiz 3

Solution: We know, Speed = Distance/Time

= 750/7*60

= 1.78 m/sec

To convert m/sec to km/hr 1.78*18/5 =6.408 km/hr

Solution:

We know, Distance = Speed *Time

=(80 x 5) = 400 km.

If, Speed = Distance/Time

Required Speed = 400/3 km/hr.

= 133.33 km/hr

Solution:

Assume,

The genuine distance Neha is covering = xkm/hr

Therefore,

x/8 = x+30/14

14x = 8x + 240

6x = 240

x = 240/6 = 40

Solution:

According to the question,

the average speed of a train, With stoppage = 120 km/hr

Without stoppage = 90 km/hr

Distance left = 120-90 = 30 km

Time consumed to cover the remaining distance = (30/120)*60 = 15hrs.

Solution: Let, the distance covered while walking = x km

Distance covered on tractor = 110 – x

Time = Distance /Speed

x/4 + (110-x)/18 = 12

9x + 220 – 2x = 432

7x = 432-220

7x = 212

x = 212/7 = 30.28 km

Solution:

We know,

Distance = Speed *Time

= (110 x 4) = 440 km.

If, Speed = Distance/Time

Required Speed = 440/2 km/hr.

= 220 km/hr

Solution:

We know,

Speed = Distance/Time

= 950/15*60 = 1.05 m/sec

To convert m/sec to km/hr 1.05*18/5 = 3.78 km/hr

Solution:

Total Distance = 670km/hr

Total time is taken when the average speed is 120km/hr = 7 hours

Total time is taken when the average speed is 80 km/hr=?

We know, Time = Distance/Speed Time = 670/80 = 8.375 hours

Solution:

The speed of the bus1 = 4x

Speed of the bus2 = 5x

According to the question,

speed of bus1 =

5x= 100/2=

x= 10

Therefore, speed of the bus1 = 4(10) = 40 km/hr