InfyTQ Numbers Quiz 3

Solution:

Let us assume that the smaller number is x

Therefore the larger number = x + 1250.

x + 1250 = 6x + 15

5x = 1235

X = 247

Correct Answer: Option a

Solution:

The square of any prime greater than 3, when divided by 12 leaves a remainder 1⋅p2 when divided by 12 leaves a remainder of 1 and 17 when divided by 12 leaves a remainder of 5. So p²+17 when divided by 12 leaves a remainder of 6.

Solution:

k+4 is divisible by 7

so k=3+7m=3,10,17,24……………. ( m=0,1,2,3,…………..)

Now let P=k+2n is divisible by 7

P=3+7m+2n

P=7m+3+2n

For to be divisible by 7 the minimum requirement is

3+2n=7t (t=1,2,3…………)

for t=1,n=2

but n>2 so putting t=2

3+2n=14

n=9

Thus the smallest value of n >2 is 9

Solution:

Let us calculate the sum of the digits of the number

= 5 + 1+ 7 + x + 3 + 2 + 4

= 22 + x, which must be divisible by 3

Therefore, x = 2

Correct Answer: Option a

Solution:

Sum of the digits = 5 + 4 + 6 + x + 8 +7+ 9

= 39 +  which must be completely divisible by 3

Therefore, x = 0


Correct Answer: Option a

Solution:

= (101)2 x (99)2

= (100 +1)2 x (100 -1)2

= 2 [(100)2 + 12]

= 2 x (10000+1)

= 2 x 10001

= 20002

Correct Answer: Option c

Let aurangabad x1=71, is subtract 0.01

71-0.01=70.99 divide by 10,get quotient 70.99/10=7.09, add 1,Y=7.09+1=8.09 0.5Y=0.5*8.09=4.045

Similarly batindha x2=48, Sub 48-0.01=47.99, divide by 10,quotient 47.99/10=4.79, add 1,Y=4.79+1=5.79

0.5Y=0.5*5.79=2.895

Adding both 4.045+2.895=7.0

Solution:

= 123456789 x (60 + 2)

= 123456789 x 60 + 123456789 x 2

= 7407407340 + 246913578


= 7654320918


Correct Answer: Option a

Solution:

It is clear that 4864 is completely divisible by 4.

Therefore, 9P2 must be completely divisible by 3

• 9 + P + 2 must be divisible by 3


• P= 1

Solution:

He could have dealt a total of 40 cards, in which case Mushtaq would get 9 cards. On getting one
card from Mushtaq, the ratio would become 4:1, while on giving away one card to Mushtaq, the
ratio would become 3:1.