InfyTQ Averages Quiz 3

Solution:

Total runs scored in $10$ matches $=10\times 28.4$

Total runs scored in first $6$matches $=6\times 42$
Sum of last 4 match = (10×28.4)–(6×42)
= 284–252 = 32
Average = \frac{32}{4}
= 8

Solution:
Average of last four numbers = (10×38.9)–(6×42)
= 389–252=137
Average = \frac{137}{4}
=34.25

Solution:

Total age of 60 students = 60 × 27 = 1620 years.
Actual age of 60 students = 1620 -44+24 = 1600 years
Actual average age = \frac{1600}{60} = 26.67 years

Solution:

Let total present age of father, mother & two sons = 53 × 4 = 212 years
Let total ages, 5 years before be 16M
by given condition,
16M = 212 – 20 = 192

M = 12
∴ Total age of both sons after 8 years = 12 × 3 + 12 × 2+ 13 + 13 = 86 years

 

Solution:
The average set S is:

\frac{(4+6+8+9+13)}{5}= 8

The average of the elements is:

\frac{(4+6+9+13)}{4}= 8

If we remove an element which equals the average, then the average of the new set will remain unchanged. Here after removing 8 the new set becomes {4, 6, 9, 13}.

Average price of 6 apples and 3 mangoes = 36 Rs

Total price= 36×9 = 324

Average price of 8 apples and 7 mangoes = 48 Rs

Total price= 48×15 = 720
Total price of 14 apples and 10 mangoes = 324+720 = 1044

Therefore, price of 140 apples and 100 mangoes = 1044 ×10 = 10440

 

Solution:
Let the total number of workers in the workshop = Y
Sum of Salaries of all workers = 11000Y
Sum of Salaries of all 8 Technicians = 8 x 12000 = 96000
Sum of Salaries of all of the rest Workers = (Y-8) x 3000 = 3000Y – 24000
11000Y = 96000 + 3000Y – 24000
Y = 9

Solution:
Average of first n natural numbers = \frac{(n+1)}{2}
Here, n = 69
Therefore,
Average of natural numbers from 1 to 69= \frac{(69+1)}{2} = 35

Solution:

Average of first n even numbers = (n+1),

Here, n (i.e. Number of terms in series) = 8,

Therefore,

Average of all even numbers from 2 to 16 = (8+1) =9

Solution:

Sum of all the odd numbers b/w 3 to 21= (3+5+7+9+11+13+15+17+19+21)= 120

Average= \frac{120}{10} = 12