InfyTQ Problems on Ages Quiz 4

Let, the current age of Preeti and Sakshi be 8x and 7x.
Given, 8x+7x = 60
15x = 60
X = 4
After 6 years their age will be, 8x+6 and 7x+6

= 8*4+6 and 7*4+6
= 38 and 34
The ratio will be 19:17

Let Reena’s age be x
Given, Anu is 8 years elder to Reena = x+8
Given, Asha is twice the age of Reena = 2x
Given, 2x + x + x+8 = 68
4x = 60
X= 15
Reema’s age is 15 years
Asha’s age is 30 years
Anu’s age is 23 years

Let Laxman’s present age be x
Given, Mohan’s present age 8 years
Then, Arav’s present age = 8-3 = 5 years
Given, if we subtract 9 years from Arav’s present age and divide the remainder by 14 we will get
Laxman’s present age
= x-9/14 = 5
x-9 = 70
x = 79 years
Laxman’s present is 79 years

Let us assume Shano’s present age as x
Given, x-6 = 5/4(x-6)
4x-24 = 5x-30
X = 6 years
If Shano’s age is 6 years then Rano’s age will be 5/4time 6
= 12.5 years.

Given, the sum of Ram, Mohan, Raj, Roy’s age is 96.
Given, after 6 years their age will be in ratio 8:7:6:9
Therefore, after 6 years their age will be 8x, 7x, 6x, 9x.
Then, the present age will be,
Ram = 8x-6
Mohan = 7x -6
Raj = 6x-6
Roy = 9x-6
Ram+Mohan+Raj+Roy = 96
= 8x-6 + 7x-6 + 6x-6 + 9x-6 = 96
30x – 24 = 96
X = 4
Raj's present age = 6x-6 = 24 - 6 = 18 years

let the age of Radha be x years.
age of Rohan be \frac{2}{5}\times x
After 7 years
age of radha=x+7
and age of rohan=\frac{2}{5}\times x+7
According to question

\frac{2}{5}\times x+7=\frac{2}{3}(x+7)
6x+105=10x+70
4x=35
x=8.75=9years(approx)

Age of radha=8.75 years

Given, Total average ages of 60 girls is 12
Therefore, total age of 60 girls = 12 x 60 = 720 years.
Given, the average ages of 20 girls is 13
Therefore, total ages of 20 girls = 20*13 = 260 years
Given, the average ages of 15 girls is 11
Therefore, total ages of 15 girls = 15*11 = 165 years
Then, average age of left over girls will be, 720 – (260+165)/ 60 – (20+15)
= 295/25 = 11.8 years

Let Sabah’s age eight years ag0 be x
Then Farah’s age eight years ago would be 2x (given Farah is twice the age of Sabah)
Sabah’s present age will be x+8
Farah’s present age will be 2x+8
Given, the ratio of their present age is 3:2
= x+8/2x+8 = 3/2
= 3x+24 = 4x+16
x = 8

Sabah’s age is 16 years and Farah’s age is 24 years
Sum of Sabah and Farah’s age is 40 years

Given, Kavya’s present age is 30 years.
Given, Kavya is thrice the age of Asha
Therefore Asha is 30/3 of Kavya
Asha is 10 years old.
The difference between their respective ages are (30-10) = 20 years

Given, Neha’s present age is 17 years
Given, product of their ages is 578
Then, Kunal’s age will be 578/17 = 34 years.
The sun of Neha and Kunal’s age is 34+17 = 51
On dividing 51 by 3, we get 17.