MyAnatomy Aptitude Questions and Answers

Solution:

10th term is zero.

So a + 9d = 0

4th term = a + 3d

= a + 9d - 6d

= -6d

9th term = a + 8d

= a + 9d - d

= -d

So, 20th term : 36th term = -6d:-d = 6:1

Solution:

This is an AP with a = 8 and d = 3

Nth term of AP = a + (n-1)d

12th term = 8 + (12-1)\times 3

= 8 + 33 = 41

Solution:

Let GM = k

Then HM = k^{2}

We know that AM x HM = HM^{2}

So AM = \frac{k^{2}}{k^{2}} = 1

Solution:

The repeating observations are

26 - 3 times

30 - 2 times

So most frequent observation is 26

So

Mode = 26

Solution:

Sum of the observations = 10 + 15 + 24 + 17 + 9 + 22 + 13 + 20

=130

Number of observations = 8

Mean  =   \frac{130}{8}

=16.25

Solution:

P = 5000

R = 10

A = 6050

Amount  = P(1 +\frac{R}{100})^{T}

6050 = 5000(1 +\frac{10}{100})^{T}

Solving, T = 2 years

Solution:

Given: P = Rs.50000, r = 7 %, n = 3 years

calculation: quarterly,

therefore, take R = 1.75%

N = 6 quarters

A = P(1 +\frac{R}{100})^{N}

A = 50000(1 +\frac{1.75}{100})^{6}

=Rs. 55485.11

Solution:

P = 5800

N = 2

CI = 594.50

CI = P(1 +\frac{R}{100})^{N} - P

594.5 = 5800(1 +\frac{R}{100})^{2} - 5800

Solving, R = 0.05

Or, R=5%

Solution:

Required probability = P(Messi) + P(Ronaldo) + P(neymar) (all the events are mutually exclusive).

= \frac{1}{6}+\frac{1}{9}+\frac{1}{8}

= \frac{29}{72}

Solution:

The probability that Sreesanth will not solve a problem = \frac{2}{3}

The probability that Sreesanth will not solve 5 problems = (\frac{2}{3})^{5}= \frac{32}{243}.

Hence, the probability that Sreesanth will solve at least one problem = 1 -  \frac{32}{243} =  \frac{211}{243}.

Solution:

Case 1 - Boy red , girl blue

P(boy red) = \frac{4}{9}.

P(girl blue) = \frac{7}{9}.

So P(case 1 ) = \frac{4}{9}\times \frac{7}{9}.

= \frac{28}{81}

Case 2 - Boy blue , girl red

P(boy blue) = \frac{5}{9}.

P(girl red) = \frac{2}{9}.

So P(case 2 ) = \frac{5}{9}\times \frac{2}{9}.

= \frac{10}{81}

So required Probability = \frac{28}{81} + \frac{10}{81}

\frac{38}{81}

Solution:

a = 5

d = 3

Sum of First 5 terms = \frac{5}{2}(2 x 5 + 4 x 3)

= 55

Sum of First 8 terms = \frac{8}{2}(2 x 5 + 7 x 3)

= 124

Sum of Next 3 terms = 124 - 55 =69

Difference = 55 - 69 = -14

Solution:

Sum of infinite GP = \frac{a}{1-r}

Here a = 1 and r = 0.9

Sum = \frac{1}{1-0.9}

= 10

Solution: Nick Robinson:Andy Buckley

= (25000\times 36):(15000\times 6+30000\times 24)

=900000:810000

=10:9

Andy Buckley's share= (247000 \times \frac{9}{19})

=Rs. 117000

Solution: Let the initial capital of Marcel Sabat and Kenneth Branagh be Rs. 2x and Rs. 3x respectively

Then, ratio of profits

= (2x\times 12):(3x\times 24)

=24x:72x

=1:3

∴Kenneth Branagh's share

= Rs.(26000\times \frac{3}{4})

=Rs. 19500