InfyTQ Time and Work Quiz 4

Let a man’s wage per day= a

And woman’s wage per day= b.

There are 24 men so, 24xa= 24a and no. Of women is16 so, 16xb= 16b.

Therefore, 24a+ 16b= 11600.---------1

According to the other part of the question,

12a+ 37b= 11600. ------------2

For solving the equations, we will multiply the equation 2 with 2 and we get,

2(12a+ 37b= 11600.)

24a+ 74b =23200.-----------3

Solving 1 and 3 we get,

58b= 11600

B= 200

Putting the value of b=200 in equation 1 we get,

24x a +16x 200= 11600

24 a + 3200= 11600

24 a= 11600- 3200

24a= 8400

A= 8400/24

A= 350

Hence, the daily wage of a man is Rs. 350."

B+ C  1 days work = ½ and B 1 day  work = 1/20
Therefore, C 1 day work = (1/12) – (1/20) = 4/120 = 1/30
Monet will be distributed according to the ratio
of work done i.e A: B: C: D
= 1/32 : 1/20 : 1/30 : 1/24 = 15 :24:16:20
Therefore, C Share = 16/(15+24+16+20) = Rs 16/3

Video solution:

A will complete (1/a) th of the job in a day.
B will complete (1/b) th of the job in a day.
A and B will complete the job in 7.5 or (15/2) days
(1/a) + (1/b) = 1 /(15/2)
(1/a) + (1/b) = 2/15 .......>1Eqn
From the question, we know that if A completes
half the job working alone and
B takes over and completes the next half, they
will take 20 days.
A can complete the job working alone in a days,
so a/2 days
B will complete the remaining half of the job in days
so b/2 days
a/2 + b/2 =20
==> a+b=40 ==> a=40–b .....>2Eqn
sub eqn(2) in Eqn(1) we get
(1/40−b) + (1/b) = 2/15
(b + 40 - b)/ b(40-b) = 2/15
40/(40b-b^2) = 2 /15
600 = 80b- 2b^2
40-b^2 = 300 (Sub by 2)
B^2 - 40b + 300 = 0
(b−30)(b−10)=0
b=30 or b=10.
If b=30, then a=40−30=10
or
If b=10, then a=40−10=30.

Let 1 boy’s day of work =x and 1 girl’s day of work = y
Then 4x+6y= 1/8
3x+7y = 1/10
Solving these equations we get y = 1/400
One girl can finish the task in 400 days
So 10 girls can finish the task in 40 days

Video solution:

Taking the lcm(12,15,20) = 60 liters (capacity of the tank)
In 1 hr : A can fill 5 liters(60/12), B = 4 liters C = 3 liters
Its given that A is open all time and B & C alternately.
So in 1st hr : A+B = 9 liters
2nd hr : A+C = 8 liters
3rd hr : A+B = 9 liters
4th hr : A+C = 8 liters
5th hr : A+B = 9 liters
6th hr : A+C = 8 liters
7th hr : A+B = 9 liters
Total = 60 liters (Capacity of the tank).
So Ans = C. 7 hours.

Bablu work = 1/10

Ashu work = 1/15

Total work = 1/10+1/15 = 3+2/30 = 5/30

Total work = 6 days

Bablu paid = 6/10*5000 = 3000

_____
OR
_____

Time taken by A and B is in the ratio of = 3:2

Ratio of the Work = 2 : 3 (Since, time and work are inversely proportional)

Total money is divided in the ratio of 2 : 3 and B gets Rs.3000

Let the money to be paid = 30 rupees.
Then George daily wage = 30/15 = 2,
and Mark daily wage = 30/10 = 3.
If both are working, then 5 rupees
to be paid. So given sum
is sufficient for 30 / 5 = 6 days.

X takes 12 days to complete the full work.
Y take 18 days, Z takes 10 days.
3 days work = 3(1/12+1/18+1/10)
= 43/60
Remaining work = 1−43/60=17/60
This work should be completed by Y in 17/60×18 = 5.1 days