Wipro WILP Ratio and Proportion Quiz- 1

Correct answer: Option II

Solution:

Correct answer: Option III

Solution:

Let the third box be Z

Then, first box = 140% of z = 140z/100 = 7/5

Then, second box = 180% of z = 180z/100 = 9/5

Therefore, ratios of the two boxes will be 7z/5 : 9z/5 = 35z : 45z =  7:9

Solution:

Let the shares be = 6x : 3x : 3x : 2x respectively

Then 3x- 2x = 1000

X = 1000

Therefore, Bharat’s share = 3x

= 3 * 1000 = 3000

Correct answer: Option II

Solution:

Let the number of seats left in the classes be = 4y and 6y

Increased seats = (120/100* 4y) (150/100*6y)

= 48y/10 , 9y

= 48:90

The ratio will be 16: 30,

= 8: 15

Correct answer: Option II

Solution:

Quantity of juice = (30 *4/6) liters = 20 litres

Quantity of water = (30- 20) = 10 litres

Another ratio = 2:4

Let the quantity of pulp to be added further be x times

Then, juice: pulp (20/10+x)

Now, (20/10+x) = 2/4

80 = 20 + 2x

x = 60/2 = 30

Correct answer: Option IV

Explanation:

Let the number of blue and red balls in the box be 4x and 8x respectively.

Their increased number is (140% of 4x) and (120% of 8x).

 

{140/100*4x} and {120/100*8x}

 

The new ratio will be = 35x/5: 15x/5

= 7: 3

Let the original salaries of Rohan and Salim be Rs. 4x and Rs. 6x respectively

Correct Answer: Option III

Solution:

(y* 3) = (0.5* 12)

= 3/6

Y= 1/2

Correct Answer: Option I

Solution:

Let the number of coins be 4x and 6x.

Total amount given = Rs.320

=> (.25)(4x) + (.50)(6x) = 320

Hence we get x = 1x + 3x = 320

X = 80

= 25 paisa coins = 320

= 50 paisa coins = 480

Suppose the container initially contains 2X and 5X of water and alcohol respectively.

Quantity of water in mixtue left =2X - 2/7 x 10 litres = 7X - 20/7 litres.

Quantity of alcohol in mixture left = 5X - 5/7 x 10 litres = 5X - 50/7 litres.

=> (7X - 20/7):(5X - 50/7) = 2/7
=> 49X - 20 = 10X - 100/7

=>39X=20 - 100/7
=> X = 40/7
i.e 2X = 2 x 40/7 = 80/7

So, the container contained 80/7 litres of water.