Wipro Time and Work Quiz-1

Rajesh can build the wall in 20 days

1 day = 1/20 of the wall

Suresh can build the wall in 15 days

1 day = 1/15 of the wall

together they can build the wall in

1/20+1/15 days

= 7/60

Hence they together can complete the wall in 60/7=8.5 or 9 days

P and Q can complete the task in 12 days.

So in 1 day, the amount of work done by them= 1/12

P and R can complete the task in 10 days

So in 1 day, the amount of work done by them= 1/10

Q and R can complete the task in 18 days

So in 1 day, the amount of work done by them= 1/18

Adding all there work=

1/12 + 1/10 + 1/18= 43/180

43/2(180) = 43/360

Hence they will complete the work in 360/43 days

 

Let the two friends be x and y


where x is slower than y

x can complete the task in 12 days

one day work will be 1/12

y is twice as fast of x so y will take 12/2 days

one day work by y = 1/6

total number of days taken by them both(working together) to complete the job = 1/12 + 1/6= 3/12 = 1/4

hence 4 days

Ashish wants to complete his apartment renovation in 25 days


Let ashish remove x number of men.

So he needs 24-x men to complete the remaining work

Let

Men= M, Days=D, Time/hours = T, Work = W

M1D1T1W2 = M2D2T2W1

Note that W2 is on left side and W1 is on right side

M1 = 24, D1 = 6, W1 = 80% of 1 = 0.8

M2 = 24-x, D2 =  4, W2 = 20% of 1 = 0.2

(24 x 6 x 0.2) = (24-X x 4 x 0.8 )

9 = x

raju is completing 25% of the work in 5 days he will complete 100% of the work in

(100/25) x 5 = 20 days

If raju will complete 100% of the work in 20 days then he will complete 10 times the work in 20 x 10 = 200 days.

24 men days + 18 women days = 20 man days + 28 woman days

→ 4 man days = 10 woman days

→ 1 man day = 2.5 woman days

Total work = 24 man days + 18 woman days = 60 woman days + 18 woman days = 78 woman days

hence, 1 man + 1 woman = 3.5 women can do it in 78/3.5 = 156/7 = 22(2/7) days.

A can do the work in 10 days

In 1 day A will do 1/10 work

B can do the work in 20 days

In one day B will do 1/20 work

A+B+C can complete the work in 5 days

In one day they will do 1/5 work

now

A's work + B's work + C's work= total work

C's work = 1/5 - (1/10 + 1/20)

= 1/5 - (3/20)

= 1/20

hence 20 days

let a and b be the time in which a and b alone can do the work respectively

1/a and 1/b will be efficiency of and be respectively

since A can do a piece of work in 20 days

a = 20

5/a + 10/b = 1

5/20 + 10/b = 1

b= 40/3

let number of days in which a and b together finish the work be n

n(1/a +1/b) = 1

n(1/20 + 3/40)= 1

n =8

together they will take  8 days

Raju being twice as good as workman as Vijay, you can solve the  following equation to get the required answer :

1/R + (1/2)R = 1/14

Solving this equation will give you 42 days