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MindTree Boats and Streams Quiz 1

Question 1

Time: 00:00:00

How long will it take to row 20 km upstream from Kolkata to Howrah for Ramesh Tyagi if he can row 10 km in 10 minutes in still water and the same distance in 8 minutes with the stream?

12 min

13.33 min

24 min

26.27 min

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Let x be the speed of man in still water and y be the speed of stream.

∴ Speed of man (x) = 60 km/hr and speed of downstream = 75 km/hr.

∴ Speed of stream = 15 km/hr.

Hence upstream speed = 60 – 15 = 45 km/hr.

So time taken to cover 20 km = 20/45*60 = 26.67min.

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Question 2

Time: 00:00:00

Himesh Rana is rowing a boat from point Himkund to Vaishali, a distance of 12 km. From Himkund it travels 4 km downstream in 15 minutes and the remaining 8 km upstream to reach Vaishali. If the downstream speed is twice as high as the upstream speed, what is the average speed of the boat for the journey from Himkund to Vaishali?

10(2/3) km/hr

9.6 km/hr

11.16 km/hr

10.44 km/hr

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4 km downstream is covered in 15 min.
∴ speed of downstream = 16 km/hr.
So speed of upstream = 8km/hr.
Total time taken for downstream journey = 15 min (given).
Now total time taken for upstream journey = 8/8 = 1 hr = 60 min.
Hence total time taken from A to B = 15 + 60 = 75 min.
As average speed = Total distance /total time, so average speed from A to B = (12/75)*60 = 48/5 = 9.6kmph.

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Question 3

Time: 00:00:00

A motorboat can travel at 5 km/hr in still water. It travelled 90 km downstream in a river and then returned, taking altogether 100 hours. Find the rate of flow of the river.

3 km/hr

3.5 km/hr

2 km/hr

4 km/hr

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Speed of boat in still water = x = 5 km/hr.
Let rate of flow of river = y km/hr.
∴ Speed of u/s = 5- y and speed of d / s = 5 + y
∴ 90/(5+y) + 90/(5-y) = 100 ⇒ y = 4 km/hr.

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Question 4

Time: 00:00:00

Mohit Gaur is a fisherman in Odisa. He can row 30 km upstream in 6 hours. If the speed of Mohit Gaur in still water is 6 km/hr, find how much he can row downstream in 10 hours.

70 km

140 km

200 km

250 km

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Speed of upstream = 30 / 6 = 5 km / hr.
Speed of man in still water = 6 km / hr.
∴ Speed of current = 6 - 5 = 1 km / hr.
So speed of downstream = 6 + 1 = 7 km / hr.
∴ Distance traveled in 7 hrs = 10 * 7 = 70 km.

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Question 5

Time: 00:00:00

Shipra Malviya is a boatman in Karnataka who can row 2 km against the stream in 20 minutes and return in 10 minutes. Find the rate of flow of the current.

2 km/hr

1 km/hr

3 km/hr

5 km/hr

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Let x be the speed of man in still water and y be the speed of current.
Speed of d / s = (2 / 10) × 60 = 12 km / hr. Speed of u / s = (2 / 20) × 60 = 6 km / hr.
∴ rate of current = (12 - 6) / 2 = 3 km/hr.

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Question 6

Time: 00:00:00

A boat takes 4 hours for travelling downstream from point A to point B and coming back to point A upstream. If the velocity of the stream is 2 kmph and the speed of the boat in still water is 4 kmph, what is the distance between A and B?

9 km

3 km

6 km

2 km

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Let the distance between A and B be x km.
Speed downstream = 6 kmph, speed upstream = 2 kmph.
(x/6) + (x/2) = 4 ⇒ 4x = 24
∴ x = 6

Distance AB = 6 km.

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Question 7

Time: 00:00:00

If Girjanandan Kar can swim in Kaveri river, downstream at 6 kmph and upstream at 2 kmph, find his speed in still water.

4 kmph

5 kmph

6 kmph

7 kmph

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Speed in still water = (1/2) * (6 + 2) km/hr = 4 km/hr

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Question 8

Time: 00:00:00

Muthuswami Ayyiar can row a boat at 10 kmph in still water in Chennai. If the speed of the stream is 6 kmph, the time taken to row a distance of 80 km down the stream is

3 hour

4 hour

5 hour

6 hour

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Speed downstream (10+6) km/hr 16 km/hr.
Time taken to cover 80 km downstream = (80/16) hrs = 5 hrs

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Question 9

Time: 00:00:00

The speed of a boat in still water in 15 km/hr and the rate of current is 3 km/hr. The distance travelled downstream in 12 minutes is

3.7 km

2.6 km

1.6 km

3.6 km

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Speed downstream = (15 + 3) kmph = 18 kmph.
Distance travelled = 18 x 12 / 60 km = 3.6 km

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Question 10

Time: 00:00:00

Rishu Patel is a boatman in Ganga River at Patna. He takes twice as long to row a distance against the stream as to row the same distance in favour of the stream. The ratio of the speed of the boat in still water and stream is

3:1

1:2

4:3

3:2

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Let speed downstream = x kmph
Then Speed upstream = 2x kmph
So ratio will be,
(2x+x)/2 : (2x-x)/2
⇒ 3x/2 : x/2 ⇒ 3:1

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