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MindTree Pseudo Code Quiz 1

Question 1

Time: 00:00:00

What will be the output of the following program

#include<stdio.h>

#include<iostream.h>

int main(){

register n = 25;

int far *x;

x=&n;

printf("%d ",*x);

return 0;

}

Address

Compilation error

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This code will show compilation error.

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Question 2

Time: 00:00:00

What will be the output of the following code statements?

integer a = 10,

b = 35, c = 5

print a * b / c - c

Compilation error

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From BODMAS rule firstly b will be divided by that will be equal to 7 then it will be multiplied by a that will be equal to 70 and at last c will be subtracted from it so the answer will be 65.

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Question 3

Time: 00:00:00

What is the output of the following code?

a=15;

b=0;

if(a=10)

Print b=7;

else b=1;

cout<< b;

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Since a is not equal to 10 therefore b=1 will be printed.

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Question 4

Time: 00:00:00

Output of the following program will be?

#include<iostream.h>

Class Car

{

int x;

}

int main()

{

Car C;

cout < return0;

}

Runtime Error

Compiler Error

Garbage Value

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This program will give Compilation Error

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Question 5

Time: 00:00:00

What is the output of this program?

class main_class {

public static void main(String args[])

{

if (i == 20) {

int j= 18;

System.out.println(i);

}

}

}

Compilation Error

Runtime error

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It wil show compilation error as there is error it can’t print a condition od if statement.

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Question 6

Time: 00:00:00

Find out the error, if any in the below program?

int j = 1;

switch(j) { printf("hello Prepster!"); case 1:

printf("case1"); break;

case 2: printf("case2"); break; }

Case 1

Case2

Both A & B

No error

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There is error in Case 1 because of switch case.

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Question 7

Time: 00:00:00

find the output of the following code

int main( )

{

int a=5, i, f1, f2, j;

if ( a < 2 )

return a;

else

{

f1 = f2 = 1;

for(i=2;i<n;i++)

{

j = f1 + f2;

f2 = f1;

f1 = j;

}

printf("%d",j) ;

}

}

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code is returning the nth term of the fibonacci series.

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Question 8

Time: 00:00:00

If the value of a=5 and b=7 what will be the output of the following function?

int fun(int a, int b)

{

if(a<=0)

return b;

else

return(fun(a-1,b-1));

}

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when the base condition is met, it will display the value of b. This is a recursive code.

Given that the value of an is 5 and that it decreases by 1 with each function call, b's value also decreases by 1 with each function call.

When the base condition is executed, the value of a will change to 0 (because it has been decreased by 1.5 times) and the value of b will change to 2 (because it has also been decreased by 1.5 times), and the result will be 2.

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Question 9

Time: 00:00:00

Choose the appropriate response after analysing the function given below.

public static void main(String[] args)

{

String names[] = new String[5];

for(int x=0; x<args.length; x++)

names[x] = args[x];

System.out.println(names[2]);

}

Null

names

Compilation error

Runtime error

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The argument's length is zero.Thus, neither time will the loop be executed.ThereforeNull will be displayed.

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Question 10

Time: 00:00:00

You must determine the proper output of the provided pseudocode, which is shown below.

int main()

{

float i = 0.0;

long int j = 10;

printf("%d", sizeof(i) == sizeof(i+j));

return 0;

}

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sizeof(i) that is float is 4

sizeof(j) that is long int is 8

sizeof(i+j) that also comes out to be float will have size = 4

here it is asking sizeof(i) == sizeof(i+j)

i.e 4 == 4

"==" operator gives result in either 0 or 1

so answer is 1.

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["0","40","60","80","100"]

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