HackerRank Alpha Numerical Series Quiz- 1

Letter  : U  -2 = S -2= Q -2 =O

Numbers : 121 (11^{2}) ----> 100 (10^{2})----->81(9^{2})------>64(8^{2})

The given sequence is a combination of two series :
1,8,5,12,? And II. P,Q,R,S
The pattern in first is : 1+7=8-3=5+7=12-3=9
So missing term is 9

Explanation:
First Number : 1+3=4+3=7+3=10+3=13
Second Letter : P+2=R+2=T+2=V+2=X
Third Letter : Z-1=Y -1=X-1=W-1=V
So the term 11VW is wrong and must be replaced by 10VW

If all the symbols from the series are removed then our series become
L 5 C L E 6 2 G S
P D
Here in this series 6 is the sixth element from the right end of the series.

There are three symbol between first vowel from the left i.e E and first consonant from right i.e. D.

5*6*2=60

After rearranging the digits in ascending order from left to right the number c=become 23456789. Here 5 and 9 are at the same position as before the rearrangement.

In the following series the first letter is moved two steps forward the next term , the number series is followed by :
1*1+1=2
2*2+2=6
6*3+3=21
The third letter is moved one step backward to form the next term . Hence following the series the next term will be Y(21*4+4)=88.

There are two alphabetical series here. The first series is with the first letters only : PQRST. The second series involves the remaining letters: CD ,EF,GH,IJ,KL.

Because the letters are the same ,concentrate on the number series , which is a simple 2,3,4,5 series , and follows each letter in order . Hence the answer is MN_{3}OP.