HackerRank Logical Questions and Answers 2025

sum of A.P. series=(n/2)(2*a+(n-1)*d)

here sum=13524,n=6,d=7

substituting these values in above eq.

solving we get a=1911

Angle traced by hour hand in 12 hours = 360 °

Angle traced by hour hand in 1 hour = 360°/12 =30°

Angle traced by hour hand in 8 hour = 8 × 30° = 240°

At 8:30, hour hand will be in middle of 8 & 9, so angle traced by hour hand at 8:30

= 240° + (30°/2) = 240° + 15° = 255° -(i)

Angle traced by minute hand in 60 minutes = 360 °

Angle traced by minute hand in 1 minute = (360°/60)= 6°

Angle traced by minute hand in 30 minutes = 30 × 6° = 180° -(ii)

Now, the angle between the two hands of a clock when time is 8:30 = 255° - 180° (from i & ii)

= 75°

after 12 o clock 12:21.......=1

from 1 to 9 it is 1.01, 1.11, 1.21, 1.31, 1.41, 1.51.= 6

similarly 2.02,2.12,.................

6*9=54+1=55

after 10 o clock 10:01, 11:11

Ans: 55+2=57

Here we can see there are 3 rows and 4 columns of cubes. Therefore, number of cubes = 4*3 = 12

Again, another set of 4 cubes are there on top of the first row. Hence total number of cubes = 12 + 4 = 16

Clearly, the two square sides will form the top and bottom. And the two rectangular blank strips will be opposite each other, and the two filled rectangular strips will be opposite each other. Since in figures B and D, the two filled rectangular sides have been shown adjacent to each other, we can say that these figures are incorrect. Options A & C on the other hand are possible.

Sun rises in the east in the morning. Since the shadow of Suresh falls to his right. So he is facing South.

The colours adjacent to yellow are orange, blue, red and rose. Hence violet will be opposite to yellow.

The hands of a clock point in opposite directions (in the same straight line) 11 times in every 12 hours. (Because between 5 and 7 they point in opposite directions at 6 o’clock only). So, in a day, the hands point in the opposite directions 22 times.

Step 1: Box 4 - Box 1 ---------> Box 10

9 - 11 = -2

Step 2: Box 10 < 0

-2 < 0 (yes)

Step 3: then Box 9 + Box 5 ---------> Box 2

2 + 7 --------> 9

Step 4: Box 2 > Box 7

9 > 7 (yes)

Then Step 5: Box 10 x Box 2 --------> Box 3

-2 x 9 ------> -18

Now checking from the options Box 7 is the only box which remains unchanged. Therefore Box 7 is the correct answer

Backtracking from the options given

If you put [Box 1] = 11 then instruction and @ Instruction 3: IS [Box 1] 11 < [Box 4]12 Yes

If you put [Box 1] = 9 then instruction and @ Instruction 3: IS [Box 1] 9 < [Box 8]10 Yes

If you put [Box 1] = 3 then instruction and @ Instruction 3: IS [Box 1] 3 < [Box 2]4 Yes

As per mention above we have to double 2,4,6,8,10 value...so loop never ends before updating upto

[Box 10] that's why our ans become 16

Reference day : May 25th Monday

Days from May 25th to July 13 = 6 + 30 +13 = 49

No of odd days : 49/7 = 0

Even numbered dice are: (II), (IV) and (VI)

Number of dots on the top face of (II) dice = 1

Number of dots on the top face of (IV) dice = 1

Number of dots on the top face of (VI) dice = 1

Therefore, the required total = 1+1+1=3