HackerRank Data Interpretation Quiz- 1

Time taken by M1 to fill 20% = 10 minutes
Hence, M1 fills 100% = 50 minutes
Time taken by M2 to fill 10% = 15 minutes
Hence, M2 fills 100% = 150 minutes
Time taken by Empty tap to empty 75% = 60 minutes
Hence, empty Tap empties 100% = 80 minutes
Let total capacity of the tank = LCM (50, 150, 80) = 1200 units
Capacity of M1 = 1200/50 = 24 units
Capacity of M2 = 1200/150 = 8 units
Capacity of empty tap = 1200/80 = 15 units
Filled tank in 1 minute = 24 + 8 – 15 = 17 units
Filled tank in 14 minutes = 14 × 17 = 238 units
Rest units = 1200 – 238 = 962 units
Capacity of M1 + M2 = 24 + 8 = 32 units
Time taken by M1 and M2 = 962/32 = 30.0625 minutes

M3 taken time to fill 15% = 45 minutes
Hence, M3 fills 100% = 300 minutes
M4 takes time to fill 30% = 30 minutes
Hence, M4 fills 100% = 100 minutes
Empty tap empties 100% = 50 minutes
Let total capacity of the tank = LCM (300, 100, 50) = 300 units
Capacity of M3 = 300/300 = 1 units
Capacity of M4 = 300/100 = 3 units
Capacity of empty tap = 300 = 6 units 50
Tank filled in 10 minutes = 10 × 1 + 10 × 3 = 40 units
Work by M3 + M4 + Empty = 1 + 3 – 6 = -2 units
Tank emptied in = 40/2 = 20 minutes

Time taken by M1 to fill 20% = 10 minutes
Hence, M1 fills 100% = 50 minutes
Time taken by T5 to fill 25 % = 35 minutes
Hence, M5 fills 100% = 140 minutes
Let empty tap empties 100% in y minutes
Let total capacity of tank = LCM (50, 140) = 700 units
Capacity of M1 = 700 = 14 units 50
Capacity of M5 = \frac{700}{140} = 5 units
Capacity of empty tap = \frac{700}{y} units
Tank filled in 1 minute = \frac{19 – 700}{y} unit
Tank filled in 50 minutes = 50 × \frac{19 – 700}{y} unit
50 × 19 – 700 = 700
19y – 700 = 14y
y = 140 minutes

M3 taken time to fill 15% = 45 minutes
Hence, M3 fills 100% = 300 minutes
Time taken by M4 to fill 30% = 30 minutes
Hence, M4 fills 100% = 100 minutes
Let capacity of the tank = LCM (150, 100) = 300 units
Capacity of M3 = 300/300 = 1 unitsCapacity of M4 = 300 = 3 units 100
Capacity of Empty tap =300/150 = 2 units
Tank filled in 1 minute = 1 + 3 – 2 = 2 units
Tank filled in 150 minutes = 300 units
So, the capacity of the tank = 300 units

Time taken by M2 to fill 10% = 15 minutes
Hence M2 fills 100% = 150 minutes
Time taken by T3 to fill 15% = 45 minutes
Hence M3 fills 100% = 300 minutes
Let capacity of tank = LCM(150, 300) = 300 units
Capacity of M2 = 300 = 2 units 150
Capacity of M3 = 300/300 = 1 unit
Let the total time = t
(T2 + T3)’s capacity = 2 + 1 = 3 units
\frac{2 × t}{2}+ \frac{3 × t}{2) = 300
5t = 600
t = 120 minutes

Total distance cover by Howrah Delhi Duronto Express = 1208 km
Total time taken by Howrah Delhi Duronto Express from Howrah to Delhi
= 11:50am – 7:30pm = 16:20 hr = 980 min
The average speed ofHowrah Delhi Duronto Express
= (Total distance cover by whole journey) / (total time)
= \frac{1208}{980} \times 60 = 73.96 kmph
If the average speed of Howrah Delhi Duronto Express increases by 20% then its new
speed = 73.96 \times \frac{120}{100} = 88.75 kmph
Time taken by Howrah Delhi Duronto Express during the journey
= \frac{1208}{88.75} \times 60 = 13 hr 37 min
The time when the Howrah Delhi Duronto Express will reach to Delhi
= 7:30pm + 13:37 hr = 9:07am

Total passengers travelling from Howrah jn to Asansol jn = 500
Total passengers got down at Asansol jn = 230
Total passengers travelling from Asansol jn to Gaya jn = 500 – 230 + 220 = 490
The number of passengers who boarded the Howrah Delhi Duronto Express from Mughal Sarai jn = 330
Hence, required ratio = 490 /330 = 49/33

Howrah Delhi Duronto Express departs from Gaya jn at 3:00am
Howrah Delhi Duronto Express arrives at Mughal Sarai jn at 6:25am
Difference = 6:25 – 3:00 = 3:25 hr
Howrah Delhi Duronto Express departs from Mughal Sarai jn at 6:40am
Howrah Delhi Duronto Express arrives at Allahabad jn at 9:20am
Difference = 9:20 – 6:40 = 2:40 hr
Howrah Delhi Duronto Express departs from Allahabad jn at 9:30am
Howrah Delhi Duronto Express arrives at Delhi jn at 11:50am
Difference = 11:50 – 9:30 = 2:20 hr
Total difference = 3:25 + 2:40 + 2:20 = 8:25 hr
Hence, Howrah Delhi Duronto Express takes 8:25 hr to reach Delhi after departing from Gaya jn.

Distance between Asansol jn to Gaya jn = 454 – 195 = 259 km
Distance between Gaya jn to Mughal Sarai jn = 752 – 454 = 298 km
Total distance between Asansol jn to Mughal Sarai jn
= (Distance between Asansol jn to Gaya jn) + (Distance between Gaya jn to Mughal Sarai jn) = 259 + 298 = 557 km
Duration between Asansol jn to Gaya jn = 2:50 am – 10:30 pm = 4:20 hr
Duration between Gaya jn to Mughal Sarai jn = 6:25am – 3:00am = 3:25hr
Total duration between Asansol jn to Mughal Sarai jn = (Duration between Asansol jn to Gaya jn) + (Duration between Gaya jn to Mughal Sarai jn)
= 4:20 + 3:25 = 7:45 hr = 465 min
Hence, required average speed = \frac{557}{465} \times 60 = 71.87 kmph

Asansol to Gaya
Distance between Howrah jn to Asansol jn = 195 km
Distance between Asansol jn to Gaya jn = 454 – 195 = 259 km
Distance between Gaya jn to Mughal Sarai jn = 752 – 454 = 298 km
Distance between Mughal Sarai jn to Allahabad jn = 1020 – 752 = 268 km
Distance between Allahabad jn to Delhi jn = 1208 – 1020 = 188 km
Hence distance between third lowest station is Asansol jn to Gaya jn = 259 km