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Cognizant Quantitative Dashboard

Coginzant Quantitative Placement Dashboard

Here are the PrepInsta Practise Cognizant Quantitative Questions & Answers for Cognizant. The Quants Previous year Papers are of medium difficulty.

Cognizant Questions & Syllabus for 2019 pattern is also provided in this Dashboard. Cognizant Quantitative Placement Papers, Cognizant Quantitative Aptitude Questions from our study materials and practise questions has been found out to increase selection chances of any student by 40%.

Check the Updated Syllabus for Cognizant here on this page here.

Note – These are only practise questions and study materials for CTS.

Free Materials

Cognizant Questions and Answers

The section has totally 16 questions and has to be also solved in 16 mins.

Tips for this section –

  • Number of Questions: 3-4 Ques
  • Difficulty Level: Low-Medium
  • Importance: Medium
  • Suggested time to solve: 40-50 Sec

Cognizant Quants Mathematical Application based Questions and Solutions

Facts about this section –

  • Number of Questions: 7-8 Ques
  • Difficulty Level: Medium
  • Importance: High
  • Suggested time to solve: 50-70 Sec

Cognizant Quantitative Advance Mathematics Papers with Solutions

Facts about this section –

  • Number of Questions: 6-8 Ques
  • Difficulty Level: Medium
  • Importance: High
  • Suggested time to solve: 1min 30 Sec

Detailed Analysis

Cognizant Detailed Syllabus and Written Paper Pattern

You can find the detailed Analysis for Syllabus for Cognizant here on this page.

Topic No. Of Questions Difficulty Importance Corr. by 90%ile Sug. Time/Quest
Basic Mathematics
– LCM & HCF
– Divisibility
– Numbers, decimal fractions and power		 Total – 5 Question
2 Ques
2 Ques
1 Ques		 2 mins Medium Medium Medium
Applied Mathematics
-Profit and Loss
– Simple and Compound Interest
– Time, Speed and Distance
– Inverse		 Total – 6 Question
2 Ques
2 Ques
1 Ques
1 Ques		 2 mins Medium Medium Medium
Engineering Mathematics
-Logarithms
– Permutation and –
– Combinations
– Probability
– Misc		 0 - 3 2 mins Medium Medium Medium

Additional Practice Questions

1. A 10 Liter mixture of milk and water contains 30 percent water. Two liters of this mixture is taken away.  How many liters of water should now be added so that the amount of milk in the mixture is double that of water?
(a) 1.4
(b) 0.8
(c) 0.4
(d) 0.7
Answer: c
Explanation:
Two liters were taken away So we have only 8 liters of mixture.
Amount of milk in 8 liters of mixture = 8 × 70% = 5.6 liters
Amount of water in 8 lit of mix = 8 - 5.6 = 2.4 liters.
Half of milk i.e half of 5.6 = 2.8 liters.
We need (2.8 - 2.4) liters water more = 0.4 lit

2. A frog can climb up a well at 3 ft per min but due to slipperiness of the well, frog slips down 2 ft before it starts climbing the next minute. If the depth of the well is 57 ft, how much time will the frog take to reach the top?
Answer: 55 min
Explanation:
As per given, in 1 min,frog climbs up 3 ft and slips down by 2 ft.
So the frog climbs only 1 ft in 1 min
So after 54 mins,it would have climbed 54ft.
At the end of 55 mins it climbs up 3 ft to make it 57 ft and come out of the well.
Once it had reached the destination,it will not slip.
So the frog will take only 55 minutes to climb up the well.

3. A rectangle has twice the area of a square. The length of the rectangle is 14 cm greater than that side of the square whereas breadth is equal to side of the square. Find the perimeter of the square?
(a) 42 cm
(b) 14 cm
(c) 56 cm
(d) 28 cm
Answer: c
Explanation:
Let side of square be x.
Then for rectangle length = 14 + x   and breadth = x.
It is given
Area of rectangle = 2 × (area of square)
length × breadth = 2(x × x)
(x + 14) × x = 2 × x2
x2 + 14x = 2x2
x2 = 14x
x = 14.
Perimeter of square = 4 × x = 56

4. A man can row a distance of 5 km in 60 min with the help of the tide. The direction of the tide reverses with the same speed. Now he travels a further 20 km in 10 hours. How much time he would have saved if the direction of tide has not changed?
(a) 5 hrs
(b) 4 hrs
(c) 12 hrs
(d) 6 hrs
Answer: d
Explanation:
He covered 5 km in 1 hour , so he might cover 20 km in 4 hours.
But he took 10 hours.
He would have saved 10 – 4 = 6 hours.

5.If half of 5 were 3, that would one-third of 10 be
(a) 5
(b) 4
(c) 3
(d) 2
Answer: b
Explanation:
Half of 5 is 2.5.  But given as 3. So take 1/2 of 5x = 3 ⇒ x = 6/5
Now 1/3 (10x) = 1/3 × 10 × 6/5 = 4.

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