Mu Sigma Averages Quiz-1

Total weight decreased = 6*3= 18 kg
New man weight = (80-18) = 62 kg.

a\'s one day work = 1/8b\'s one day work = 3/8c\'s one day work = 5/8(a+b+c)\'s one day work = (1/8 + 3/8 + 5/8) = 9/8.there fore they can complete the work in 8/9 days.

Originally let there be x men.

Less men, More days (Indirect Proportion)

Therefore, (x-10) : x :: 100 :110

=> (x - 10) * 110 = x * 100 => x= 110

The average is given by →
Sum of observations / Number of observations.

So , Sum of Numbers will be given by →
Average × Number of observations.

The average of Eight numbers is 14.
Then , sum of eight numbers is →

Average × Number of observations
= 14×8
=112

Average of Six numbers is 16.
Then sum of six numbers →

Average× number of observations
= 16×6
=96

Sum of excluded two numbers will be→

Sum of eight numbers - Sum of six numbers

= 112 - 96
= 16

Therefore , if sum of remaining two numbers is 16 , Then their average =

16/2
= 8

Answer→ The average of remaining two numbers is 8

A+B=132
B+C=130
C+D=102
B+D=116
A+2B+C=262
B+C+2D=218
A+B-2D=44
132-2D=44
D=44

Let the 6 numbers be x1, x2, x3, x4, x5 and x6
Given average of 6 numbers = 30
Hence (x1+ x2 + x3 + x4 + x5 + x6)/6 = 30
Therefore, x1+ x2 + x3 + x4 + x5 + x6 = 180 → (1)
Similarly, average of first numbers = 25
Hence (x1+ x2 + x3 + x4)/4 = 30
Therefore, x1+ x2 + x3 + x4 = 120 → (2)
Subtract (2) from (1) we get
x5 + x6 = 60 → (3)
It is also given that the average of last 3 numbers = 35
Hence (x4 + x5 + x6)/3 = 35
Therefore, x4 + x5 + x6 = 105 → (4)
Subtract (3) from (4), we get
x4 = 45
Thus the fourth number is 45.

let the numbers are x1,x2,...x10.
so x1+x2+...+x10=7*10=70.
=>12*(x1+x2+...+x10)=12*70
=>average is 12*7=84

Let the average after 7th inning = x
Then average after 16th inning = x - 3

16(x-3)+87 = 17x

x = 87 - 48 = 39

Video solution:

The average of first 3 = 16 The average of last 3 = 15 The last number =18 Solution:- Sum of Last 3 numbers= 15*3=45 Hence the last number is 18 So, Sum of 2nd & 3rd = 45-18= 27 Again sum of first three numbers =16*3=48 Therefore the 1st number will be: sum of 1st 3 number-sum of 2nd & 3rd number i.e. 48-27=21

So the answer is 21.

We\'re told that 3 YEARS AGO, the average age of a family of 5 members was 17 years.

This means that the SUM of their ages was (5)(17) = 85 years.

A baby was born (meaning that there are now 6 family members). We\'re told that the PRESENT average age of the family members is the SAME.

This means that the sum of the ages is (6)(17) = 102 years.

We\'re asked for the PRESENT age of the baby.

Since each of the original 5 family members has aged 3 years since the initial average was calculated, the sum of their PRESENT ages is...

85 + (5)(3) = 100.

Since the current sum of the 6 family members is 102, the baby is 102-100 = 2 years old.