Percentages Quiz 1

Virat Kohli's Salary  = 50% of Pujara = 50% of (40% of Raina)

= (50/100)×[(40/100)×100] % of Raina =

= 20% of Raina

Saving  = 50% of (100 - 35)% of (100 - 25)% of Rs. 20,200

= Rs. (\frac{50}{100}\times \frac{65}{100}\times \frac{75}{100}\times 20200)

= Rs. 4923.75.

Let the original number be x.

Final number obtained = 120% of (80% of x) =\frac{120}{100}\times \frac{80}{100} x = \frac{96}{100} x.

 

x-\frac{96}{100} x=20

∴x =500

Explanation :

Let original consumption = 100 kg and new consumption = x kg,

So,

100 × 10 = x × 12.50

⇒x = 80kg

Reduction in consumption = 20%.

We have P = 84560, R = 10 and n = 6

Therefore, the purchase price of the machine

=\frac{ P}{(1 - (R/100))^n} =\frac{84560}{(1 - (18/100))^6}

= 84560 × (100/82) × (100/82) × (100/82) × (100/82) × (100/82) × (100/82)

= 278,151.

Total  = 100

Technician = 60

Non - Technician = 40

Permanent employees = 40% of 60 + 60% of 40

= 24 + 24

= 48

Temporary employees =  100 - 48

= 52

Let the number of students in the class be 100 and let this required average be x.

Then, (20 × 35) + (25 × 90) + (55 × x) = (100 × 65)

∴x = 64.5

Total money = Rs.[600×(25/100) + 1200×(50/100)] = Rs. 750.

 

25 paise coins removed = Rs. (600×12/100) = Rs. 72.

 

50 paise coins removed = Rs. (1200×24/100)= Rs. 288.

 

Money removed =Rs.(72×25/100 + 288×50/100)  = Rs. 162.

 

Required percentage = (162/750×100)% = 21.6 %.

It cannot be determined as no value related to amount of earning is provided

Let total population = p

number of males = 4p/9

number of females =(p-4p/9) = 5p/9

married males = 60% of 4p/9 = 30 × 5p/100 × 9 = 4p/15

married females = 4p/15

unmarried females =(5p/9 - 4p/15) = 13p/45

Percentage of unmarried females in the total males = \left(\frac{\frac{13p}{45}}{\frac{4p}{9}} \right )\times 100 = 65%