Reliance Jio Algebra Quiz 1

Answer: (C)

Explanation:

x3+y3 = (x + y) × (x2 − xy + y2)

Putting given values of x3+y3 and (x + y)

9 = 3 × ((x+y)2 − 3xy)

= 3 × (9 − 3xy)

= 27 − 9xy

9xy = 18

xy = 2

x4 + y4 = (x2 + y2)2 - 2x2y2

= (x2 + y2)2 - 2*4

[Putting value of xy]

= ((x + y)2 - 2xy)2 - 2*4

[Putting values of (x+y) and xy]

= (9 - 4)2 - 2*4

= 17

Answer: (A)

Explanation:

x3 + 1/8x3 + 3.x.1/2x(x + 1/2x) = (x+1/2x)3

x3 + 1/8x3 + 3 = 23

x3 + 1/8x3 = 5

8x3 + 1/x3 = 5.8 = 40

Answer: (D)

Explanation: say x=1

17!=13for, x=2 and 3 also not possible

x=4

52+12=132

169=169

Answer: (B)

Explanation

E= 1/√2+1 - √2+1 = 1-(√2+1)²/ √2+1

so, E= 1-(2+2√2+1)/√2+1= -2-2√2/√2+1 = -2

Solution: 2

Answer: (C)

Explanation:

9848 x 125 = 9848 x (250 / 2)

= 4924 x (500 / 2)

= 2462 x (1000 / 2)

= 1231 x (1000)

= 1231000

Answer: (D)

Explanation: If sum of digits are divisible by 9, number is also divisible by 9

96381…..9+6+3+8+1= 27    (/)

46729…..4+6+7+2+9= 28    (x)

54459…..5+4+4+5+9= 27    (/)

85369…..8+5+3+6+9= 31    (x)

46818…..4+6+8+1+8= 27    (/)

Answer: (B)

Solution: 3

Solution: 1

x2+1/12x+y2=x2+2(1/24)x+y2