Reliance Jio Aptitude Questions and Answers 2023

s_{n} =\frac{n}{2}[2a+(n-1)\times d]

s_{n} =\frac{30}{2}[2\times 5 +(30-1)\times 3] = 1455

Captain can be selected in ^{30}\textrm{C}_{1}

Vice - captain can be selected in  ^{29}\textrm{C}_{1}

Total number of ways = 30 \times 29 = 870

C.P= \frac{(100 \times  Selling price)}{(100+profit)}

=  \frac{(100 \times  300)}{(100-25)} = 400

We know Volume of cylinder = \pi r^{2} h

Volume of First cylinder = \pi 2^{2} h

Volume of Second cylinder = \pi 3^{2} h

Ratio = 4:9

4 men can repair a Road in 8 hours

To Repair Road in 1 hour we need 8\times 4 = 32  men Required

To Repair Road in 2 hour we need 8\times 4 = \frac{32}{2} = 16  men Required

3^{5} = 243

After comparing value of x = 5

\frac{7}{8} \times \frac{3}{4} = \frac{21}{32}

Let numbers are 2x : 3x

Product = 6x^{2}

According to question

6x^{2} = 6

=> x^{2} = 1

x = 1

So HCF = 1

Time right now = 4: 40 PM

the bus arrived 3 min ago so 4:40 - 0:03 = 4:37

late 2 mins so right time should be 4:37 - 0.02 = 4:35

next bus timing is 4:45

interval timing 4:45- bus expected time 4:35 = 0.10 min

so next bus will be at = 4:45+0.10= 4 :55 PM

work done by Rohit in one day= \frac{1}{10}

work done by Anup in a day= \frac{1}{15}

work done by both in a day= \frac{1}{10} +\frac{1}{15}  = \frac{10}{60}

days required by both = \frac{60}{10} = 6

Total number of Student =1000

Number of student passed first exam is 400, so probability is \frac{400}{1000}= 0.4

Number of student passed second exam is 450, so probability is = \frac{450}{1000}= 0.45

Number of student passed both exam is 50, so probability is = \frac{50}{1000}= 0.05

From probability addition rule,

P(A ∪ B) = P(A) + P(B) - P(A∩B)

P(A ∪ B) = 0.4  + 0.45 - 0.05

P(A ∪ B) = 0.80

\frac{3}{8} \times 100 = 37.5%

Required decimal = \frac{1}{60} = 0.0166

Due to stoppages, it covers 60 - 50 = 10 km less.

Time taken to cover 10 km  = \frac{10}{60} \times 60 = 10 minutes

Total runs = 34 \times 10= 340

New Average = 34 + 6 = 40

Total Runs after 11th Innings = 40 \times 11 = 440

Runs required = 440 - 340 = 100