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Quiz – 1

Question 1

Time: 00:00:00

A person crosses a 600 m long street in 5 minutes. What is his speed in km per hour?

3.6

7.2

8.4

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Explanation:

Speed = (600)/(5*60) m/sec

= 2 m/sec.

Converting m/sec to km/hr

2* (18/5) km/hr

7.2 km/hr.

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Question 2

Time: 00:00:00

An aeroplane covers a certain distance at a speed of 240 kmph in 5 hours. To cover the same distance in 1 {2}/{3}hours, it must travel at a speed of:

300 kmph

360 kmph

600 kmph

720 kmph

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Explanation:

Distance = (240 x 5) = 1200 km.

Speed = Distance/Time

Speed = 1200/(5/3) km/hr. [We can write 1 {2}/{3} hours as 5/3 hours]

required speed = (1200) * (3/5) km/hr = 720 km/hr

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Question 3

Time: 00:00:00

If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:

50 km

56 km

70 km

80 km

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Let the actual distance travelled be x km.

Then x/10 = (x + 20)/14

4x = 10x + 200

4x = 200

x = 50 km.

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Question 4

Time: 00:00:00

A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:

100 kmph

110 kmph

120 kmph

130 kmph

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Let speed of the car be x kmph

Then, speed of the train = (150/100)x = (3/2)x kmph

75/x = 75/{3/2(x)} = 125/10 * 60

= 75/x -50/x = 5/24

= x = 120 kmph

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Question 5

Time: 00:00:00

Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?

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Explanation:

Due to stoppages, it covers 9 km less.

Time taken to cover 9 km = {9/54 * (60 )} min = 10 min

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Question 6

Time: 00:00:00

The ratio between the speeds of two trains is 7 : 8. If the second train runs 400 km in 4 hours, then the speed of the first train is

70 km/hr

75 km/hr

84 km/hr

87.5 km/hr

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Let the speed of two trains be 7x and 8x km/hr

Then, 8x =(400/4) = 100

x = (100/8) = 12.5

Speed of first train = (7 x 12.5) km/hr = 87.5 km/hr.

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Question 7

Time: 00:00:00

A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is

35.55 km/hr

36 km/hr

71.11 km/hr

71 km/hr

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Total time taken = (160/64 + 160/80) hrs = 9/2 hrs.

Average speed = (320 * 2/9) km/hr = 71.11 km/hr

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Question 8

Time: 00:00:00

In covering a distance of 30 km, Abhay takes 2 hours more than Sameer. If Abhay doubles his speed, then he would take 1 hour less than Sameer. Abhay's speed is:

5 kmph

6 kmph

6.25 kmph

7.5 kmph

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Explanation:

Let Abhay\'s speed be x km/hr

then , 30/x -30/2x = 3

6x = 30

x = 5 kmph

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Question 9

Time: 00:00:00

A farmer travelled a distance of 61 km in 9 hours. He travelled partly on foot @ 4 km/hr and partly on bicycle @ 9 km/hr. The distance travelled on foot is:

14 km

15 km

16 km

17 km

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Explanation:

Let the distance travelled on foot be x km.

Then, distance travelled on bicycle = (61 -x) km.

So, x/4 + (61-x)/9 = 9

9x + 4(61 -x) = 9 x 36

5x = 80

x= 16 km

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