First Naukri Letter Series Quiz 1

Explanation:

This series consists of letters in a reverse alphabetical order

Solution:

Center letter of Every word is a prime number

DEF- E= 5

JKL- K = 11

PQR- Q = 17

After analysing the options, LMN is the right answer as, M = 13

Solution:

B, C, D, F, G, H, J, K, L, M, N, P, Q, R, S, T, ____

The given series consists of consonants in increasing order, starting with B.

The next consonant in the series is V.

Solution: The series above is given in the form:

A + 2 = C

C + 5 = H

H + 10 = R

R + 17 = I

I + 26 = I

I + 37 = T

The series 2, 5, 10, 17, 26, and 37 is obtained by +3, +5, +7, +9, +11

Therefore, the missing term is T.

Solution:

Sum of position of letters is a prime number i.e.,

ABD = 7

BCF = 11

ACI = 13

So from the option BGH is the right answer as BGH = 17

Solution:

F+5, K+5, P+5, U+5, Z+5, __

The next letter in the series is Z + 5 = E.

Solution:

Every set of words is in reversible order with a gap of 1 letter, now option A, and B are also in reversible order but do not have a gap of 1 letter, and Option D has a gap of 1 letter but it is in ascending order. Whereas, Option C is in reversible order as well as with a gap of 1 letter.

Solution:

The second and fourth letters in the series, L and A, are static. The first and third letters consist of an alphabetical order beginning with the letter H.

Explanation:

In this series, the third letter is repeated as the first letter of the next segment. The middle letter, A, remains static. The third letters are in alphabetical order, beginning with Q.

Solution:

In this series, the letters remain the same: ABC. The subscript numbers follow this series: 1,1,1; 1,1,2; 1,2,2; 2,2,2; 2,2,3.