First Naukri Clocks and Calendar Quiz -1

Solution:

Number of day from 2nd Jan 2012 till 15 August 2013:

=365 + 31 + 28 + 31 + 30 + 31 + 30 + 31+15 = 592

Therefore, Remainder = 592 modulo 7 = 4

So Independence day is on Thursday

Note: We will take no. of days in January of 2012 = 30 as 1st Jan is already there.

Solution:

We know 14th January, 1987= Monday.

Also, every year a date gets shifted forward to the next day. That means after 34 years, 14th January would shift ahead by 34 days.

Also, there would be leap years and they would result in 2 days’ shift.

 

Leap years between 1987-2021 = 1988, 1992, 1996, 2000, 2004, 2008, 2012, 2016, 2020.

⇒ Day on 14th January, 2021 = Monday + 34 + 9(for 9 leap years) = Monday + 43 days = Monday + 1 days = Tuesday

 

∵ 14th January, 2021 is a Tuesday.

⇒ 14th December, 2021 = Tuesday + (17+28+31+30+31+30+31+31+30+31+30+14) days = Tuesday + 334 days = Tuesday + 5 days = Sunday

Solution:

The clock was 9 minutes late at 5 pm on Sunday and 7 minutes ahead at 3 pm on Tuesday.

Thus, the clock has gained:

16 minutes in 7(from Sunday after 5 pm) + 24(complete Monday) + 15 ( 12 am to 3 pm on Tuesday) = 46 hours

So 9 minutes will be gained in \frac{46}{16}\times 9= 25.875 hours

we have 0.875 hours = 0.875 × 60 = 52.5 min

Therefore total time after 5 pm on Sunday = 25 hours 52.5 min

Thus, the clock will show the correct time at about 6:52 pm on Monday.

Solution:

At 12:00:00, all the clocks were correct.

At 13:00:00, the wall clock showed 12:50:00. The wall clock moved 300° in 60 minutes.

When the wall clock showed 13:00:00, the elapsed time was 360° × 60 minutes/300° = 72 minutes, so the actual time was 13:12:00.

At 13:12:00, the table clock showed 13:10:00. The table clock moved 420° in 72 minutes.

When the table clock showed 13:00:00, the elapsed time was 360° × 72 minutes/420° = 432/7 minutes, so the actual time was approximately 13:01:43

At 13:01:43 the alarm clock showed 12:55:00. The alarm clock moved 330° in 432/7 minutes.

When the alarm clock showed 13:00:00, the elapsed time was 360° × (432/7 minutes)/330° 5184/77 minutes, so the actual time was approximately 13:07:19.

At 13:07:19 the wrist watch showed 13:05:00. The wrist watch moved 390° in 5184/77 minutes.

6 hours = 360 minutes

360 minutes × 390°/(5184/77 minutes) = 2085.416667°

At 18:00:00, the wrist watch shows 17:47:34, or about 5:47pm

Solution:

Let the present time be x

According to the question,

\frac{3x}{4} + \frac{(24-x)}{5} =x\ \Rightarrow 15x+4(24-x)=20x

⇒ x = 10.667

∴ Present time= 10:40

Solution:

It is known that local time varies only with longitudes.

The flight traveled from 110E to 60W longitudes i.e. 170° longitudes.

Time change because of longitude change as 4 minutes/degree

Therefore, for 170°, time changes = 170 × 4 = 680 minutes = 11 hours and 20 minutes.

Time at 18N110E after 17 hour journey = 7AM + 17 hours =12 AM

Because the flight traveled towards west from east, the local time at 36N 60W

= 12 AM – 11 h 20 m

= 12:40 PM

Solution:

Time difference between 3 am on Saturday and 10 am on Monday= 2 days and 7 hours

= 48 + 7 = 55 hours.

We know that the clock gains 9 seconds in 3 hours, i.e. 3 seconds in 1 hour.

Hence, in 55 hours, it will gain 55 × 3 seconds = 165 seconds.

Hence, At 10 am on Tuesday it will show 10:02:45 am

Solution:

In an ordinary year, there are 365 days which means 52 weeks and 1 odd day but in a leap year, there are 366 days which means 52 weeks and 2 odd days.

So, between 1998 and 2007, 2000 and 2004 are leap years.

So, total odd days = 12 days.

As given the Buddh Purnima in 1998 falls on Tuesday

So, Thursday + 12 odd days =  Thursday + 5 odd days = Tuesday

Hence, the Buddha Purnima will fall on Tuesday in 2007.

Solution:



Clearly, the minute hand will point towards the South-west direction.

Solution:

All the three clocks will show the true time again when the faulty clock which loses 1 min/day will be 12 hours behind the correct time

& the faulty clock which gains 1 min/day will be 12 hours ahead of the correct time.

∴ Total minutes in 12 hours = 12 × 60 = 720 minutes

∵ the fault is 1 minutes per day,

Hence, the number of days required = 1 × 720 = 720 days