DXC Technical Interview Questions

// Palindrome program in C
#include 

// Palindrome is a number that is same if read forward/backward
// Ex : 12321
int main ()
{
    int num, reverse = 0, rem, temp;
    num=11211;
    printf("The number is :%d\n",num);
 
    temp = num;
    
    //loop to find reverse number
    while(temp != 0)
    {
        rem = temp % 10;
        reverse = reverse * 10 + rem;
        temp /= 10;
    };
    
    // palindrome if num and reverse are equal
    if (num == reverse)
        printf("%d is Palindrome\n", num);
    else
        printf("%d is Not Palindrome\n", num);

}
// Time Complexity : O(N)
// Space Complexity : O(1)
// Where N is number of digits in num

public class Main
 {
   public static void main (String[]args)
   {
     //variables initialization
     int num = 12021, reverse = 0, rem, temp;

       temp = num;
     //loop to find reverse number
     while (temp != 0)
       {
     	rem = temp % 10;
     	reverse = reverse * 10 + rem;
     	temp /= 10;
       };

     // palindrome if num and reverse are equal
     if (num == reverse)
       System.out.println (num + " is Palindrome");
     else
       System.out.println (num + " is not Palindrome");
   }
 }

//C++ Program to check whether a number is palindrome or not
#include 
using namespace std;

//main program
int main ()
{
    //variables initialization
    int num, reverse = 0, rem, temp;
    num=12321;
    cout <<"\nThe number is: "<<num; 
   
 
    temp = num;
    //loop to find reverse number
    while(temp != 0)
    {
        rem = temp % 10;
        reverse = reverse * 10 + rem;
        temp /= 10;
    };
    
    // palindrome if num and reverse are equal
    if (num == reverse)
        cout << num << " is Palindrome";
    else
        cout << num << " is not a Palindrome";

}
// Time Complexity : O(N)
// Space Complexity : O(1)
// where N is the number of digits in num

num = 1221
temp = num
reverse = 0
while temp > 0:
    remainder = temp % 10
    reverse = (reverse * 10) + remainder
    temp = temp // 10
if num == reverse:
  print('Palindrome')
else:
  print("Not Palindrome")