Cognizant GenC Coding Questions and Answers 2025

September 17, 2024

Coding Questions and Answers pdf

Cognizant GenC has changed the exam pattern for the year 2025. They have divided the written test into two rounds:

Round-1(Aptitude Assessment)
Round-2(Communication Assessment)
Round-3)Coding Assessment)

Coding Section Details

Topics	Details
No. of Questions	4 (2(easy) + 2(hard))
Time Limit	50 mins + 50 mins
Difficulty Level	high
Package Offered	6 LPA

Question-1

Problem Statement – Write a program to calculate the fuel consumption of your truck.The program should ask the user to enter the quantity of diesel to fill up the tank and the distance covered till the tank goes dry.Calculate the fuel consumption and display it in the format (liters per 100 kilometers).

Convert the same result to the U.S. style of miles per gallon and display the result. If the quantity or distance is zero or negative display ” is an Invalid Input”.

[Note: The US approach of fuel consumption calculation (distance / fuel) is the inverse of the European approach (fuel / distance ). Also note that 1 kilometer is 0.6214 miles, and 1 liter is 0.2642 gallons.]

The result should be with two decimal place.To get two decimal place refer the below-mentioned print statement :

float cost=670.23;

System.out.printf(“You need a sum of Rs.%.2f to cover the trip”,cost);

Sample Input 1:

Enter the no of liters to fill the tank

20

Enter the distance covered

150

Sample Output 1:

Liters/100KM

13.33

Miles/gallons

17.64

Explanation:

For 150 KM fuel consumption is 20 liters,
Then for 100 KM fuel consumption would be (20/150)*100=13.33,
Distance is given in KM, we have to convert it to miles (150*0.6214)=93.21,
Fuel consumption is given in liters, we have to convert it to gallons (20*0.2642)=5.284,
Then find (miles/gallons)=(93.21/5.284)=17.64

Sample Input 2:

Enter the no of liters to fill the tank

-5

Sample Output 2:

-5 is an Invalid Input

Sample Input 3:

Enter the no of liters to fill the tank

25

Enter the distance covered

-21

Sample Output 3:

-21 is an Invalid Input

C

Java

Python

C

Run

#include<stdio.h>
#include<stdlib.h>
int main () {
  printf ("Enter the no of liters to fill the tank\n");
  int ltt;
  scanf ("%d", <t);
  
  double lt = (ltt * 1.00);
  if (ltt < 1){
      
    printf ("%d is an Invalid Input\n", ltt);
    exit (0);
    }
  
  printf ("Enter the distance covered\n");
  int diss;
  scanf ("%d", &diss);
  double dis = (diss * 1.00);
  if (diss < 1){
    printf (" %d is an Invalid Input\n", diss);
    exit (0);
    }
  double hundred = ((lt / dis) * 100);
  printf ("Liters/100KM\n");
  printf ("%.2f\n", hundred);
  double miles = (dis * 0.6214);
  double gallons = (lt * 0.2642);
  double mg = miles / gallons;
  printf ("Miles/gallons\n");
  printf ("%.2f\n", mg);
  
  return 0;
}

Java

import java.util.*;
import java.text.*;
class Main{
public static void main (String[] args) {
DecimalFormat df2 =new DecimalFormat("0.00");
Scanner sc= new Scanner (System.in);

System.out.println("Enter the no of liters to fill the tank");
int ltt =sc.nextInt();
double lt= (ltt*1.00);

if(ltt<1){
System.out.println(ltt+" is an Invalid Input");
System.exit(0);
}
System.out.println("Enter the distance covered");
int diss =sc.nextInt();
double dis= (diss*1.00);

if(diss<1){
System.out.println(diss+" is an Invalid Input");
System.exit(0);
}

double hundered = ((lt/dis)*100);
System.out.println("Liters/100KM");
System.out.println(df2.format(hundered));

double miles = (dis*0.6214);
double gallons =(lt*0.2642);
double mg = miles/gallons;
System.out.println("Miles/gallons");
System.out.println(df2.format(mg));
}
}

Python

import sys
print("Enter the no of liters to fill the tank")

ltt =int(input())

lt= (ltt*1.00)

if(ltt<1):
    print("{} is an Invalid Input".format(ltt))
    sys.exit()

print("Enter the distance covered")

diss =int(input())

dis= (diss*1.00)

if(diss<1):
    print("{} is an Invalid Input".format(diss))
    sys.exit()

hundred = ((lt/dis)*100)

print("Liters/100KM")

print(round(hundred,2))

miles = (dis*0.6214);

gallons =(lt*0.2642);

mg = miles/gallons;

print("Miles/gallons")

print(round(mg,2))

Question-2

Problem Statement – Vohra went to a movie with his friends in a Wave theatre and during break time he bought pizzas, puffs and cool drinks. Consider the following prices :

Rs.100/pizza
Rs.20/puffs
Rs.10/cooldrink

Generate a bill for What Vohra has bought.

Sample Input 1:

Enter the no of pizzas bought:10
Enter the no of puffs bought:12
Enter the no of cool drinks bought:5

Sample Output 1:

Bill Details

No of pizzas:10
No of puffs:12
No of cooldrinks:5
Total price=1290

ENJOY THE SHOW!!!

C

Java

Python

C

Run

#include<stdio.h>
#include<stdlib.h>
int main () {
  int totalprice;
  printf ("Enter the no of pizzas bought:\n");
  int pizza;
  scanf ("%d", &pizza);
  printf ("Enter the no of puffs bought:\n");
  int puffs;
  scanf ("%d", &puffs);
  printf ("Enter the no of cool drinks bought:\n");
  int coolDrinks;
  scanf ("%d", &coolDrinks);
  int pizzaa = pizza * 100;
  int puffss = (puffs) * 20;
  int coolDrinkss = (coolDrinks) * 10;
  printf ("Bill Details\n");
  printf ("No of pizzas: %d\n", pizza);
  printf ("No of puffs: %d\n", puffs);
  printf ("No of cooldrinks: %d\n", coolDrinks);
  totalprice = pizzaa + puffss + coolDrinkss;
  printf ("Total price= %d\n", totalprice);
  printf ("ENJOY THE SHOW!!!");
  return 0;

}

Java

import java.util.Scanner;
public class Main
{
    public static void main (String[]args)
    {
        int totalprice;
        Scanner sc = new Scanner (System.in);
System.out.print ("Enter the no of pizzas bought:");
int pizza = sc.nextInt ();

System.out.print ("Enter the no of puffs bought:");
int puffs = sc.nextInt ();

System.out.print ("Enter the no of cool drinks bought:");
int coolDrinks = sc.nextInt ();

int pizzaa = Math.abs (pizza) * 100;
int puffss = Math.abs (puffs) * 20;
int coolDrinkss = Math.abs (coolDrinks) * 10;

System.out.println ("Bill Details");
System.out.println ("No of pizzas:" + pizza);
System.out.println ("No of puffs:" + puffs);
System.out.println ("No of cooldrinks:" + coolDrinks);

totalprice = pizzaa + puffss + coolDrinkss;
System.out.println ("Total price=" + totalprice);
System.out.println ("ENJOY THE SHOW!!!");
}
}

Python

pizza_count=int(input('Enter the no of pizzas bought:'))
puffs_count=int(input("Enter the no of puffs bought:"))

drinks_count=int(input("Enter the no of cool drinks bought:"))

bill=pizza_count*100 + puffs_count*20 + drinks_count*10

print("Bill details")

print("No of pizzas:{}".format(pizza_count))

print("No of puffs:{}".format(puffs_count))

print("No of cooldrinks:{}".format(drinks_count))

print("Total price={}".format(bill))

print("ENJOY THE SHOW!!!")

Question-3

Problem Statement – Ritik wants a magic board, which displays a character for a corresponding number for his science project. Help him to develop such an application.
For example when the digits 65,66,67,68 are entered, the alphabet ABCD are to be displayed.
[Assume the number of inputs should be always 4 ]

Sample Input 1:

Enter the digits:
65
66
67
68

Sample Output 1:

65-A
66-B
67-C
68-D

Sample Input 2:

Enter the digits:
115
116
101
112

Sample Output 2:

115-s
116-t
101-e
112-p

C

Java

Python

C

Run

#include<stdio.h>
#include<stdlib.h>
int main(){
    printf("Enter the digits: \n");

    int a,b,c,d;
    scanf("%d%d%d%d",&a,&b,&c,&d);

    char q=(char)a;
    char w=(char)b;
    char e=(char)c;
    char r=(char)d;

    printf("%d - %c\n",a,q);
    printf("%d - %c\n",b,w);
    printf("%d - %c\n",c,e);
    printf("%d - %c\n",d,r);

return 0;
}

Java

import java.util.Scanner;
public class Main
{
public static void main (String args[])
{
Scanner in = new Scanner (System.in);
System.out.println ("Enter the digits: ");

int a = in.nextInt ();
int b = in.nextInt ();
int c = in.nextInt ();
int d = in.nextInt ();

char q = (char) a;
char w = (char) b;
char e = (char) c;
char r = (char) d;

System.out.println ();
System.out.print (a);
System.out.println ("-" + q);

System.out.print (b);
System.out.println ("-" + w);

System.out.print (c);
System.out.println ("-" + e);

System.out.print (d);
System.out.println ("-" + r);
}
}

Python

a=int(input())
b=int(input())

c=int(input())

d=int(input())

print(str(a)+"-"+chr(a))

print(str(b)+"-"+chr(b))

print(str(c)+"-"+chr(c))

print(str(d)+"-"+chr(d))

Question-4

Problem Statement – FOE college wants to recognize the department which has succeeded in getting the maximum number of placements for this academic year. The departments that have participated in the recruitment drive are CSE,ECE, MECH. Help the college find the department getting maximum placements. Check for all the possible output given in the sample snapshot

Note : If any input is negative, the output should be “Input is Invalid”. If all department has equal number of placements, the output should be “None of the department has got the highest placement”.

Sample Input 1:

Enter the no of students placed in CSE:90
Enter the no of students placed in ECE:45
Enter the no of students placed in MECH:70

Sample Output 1:

Highest placement

CSE

Sample Input 2:

Enter the no of students placed in CSE:55
Enter the no of students placed in ECE:85
Enter the no of students placed in MECH:85

Sample Output 2:

Highest placement

ECE

MECH

Sample Input 3:

Enter the no of students placed in CSE:0
Enter the no of students placed in ECE:0
Enter the no of students placed in MECH:0

Sample Output 3:

None of the department has got the highest placement

Sample Input 4:

Enter the no of students placed in CSE:10
Enter the no of students placed in ECE:-50
Enter the no of students placed in MECH:40

Sample Output 4:

Input is Invalid

C

Java

Python

C

Run

#include<stdio.h>
#include<stdlib.h>
int main () {
    int cse;
    int ece;
    int mech;
    // Take user input
    printf ("Enter the no. of students placed in CSE: ");
    scanf ("%d", &cse);
    printf ("Enter the no. of students placed in ECE: ");
    scanf ("%d", &ece);
    printf ("Enter the no. of students placed in MECH: ");
    scanf ("%d", &mech);
  
    // If any integer is negative, print message and exit
    if (cse < 0 || ece < 0 || mech < 0){
      printf ("Input is Invalid\n");
    				// If all values are equal, print message and exit else { if (cse == ece && ece == mech && mech==cse) { printf("None of the department has got the highest placement\n"); } //System.out.println("Highest Placement:"); // First, check if any two values are equal and greater than the third else if (cse == ece && cse > mech)
  
    printf ("Highest Placement:\n");
    printf ("CSE\n");
    printf ("ECE\n");
  }
  else if (cse == mech && cse > ece){
    printf ("Highest Placement:\n");
    printf ("CSE\n");
    printf ("MECH\n");
  }
  else if (ece == mech && ece > cse){
    printf ("Highest Placement:\n");
    printf ("ECE\n");
    printf ("MECH\n");
  
  }
  else if (cse > ece && cse > mech){
    printf ("Highest Placement:\n");
    printf ("CSE\n");
  }
  else if (ece > mech){
    printf ("Highest Placement:\n");
    printf ("ECE\n");
  }
  else{
    printf ("Highest Placement:\n");
    printf ("MECH\n");
  }

return 0;

}

Java

import java.util.Scanner;
public class Main {
  public static void main (String[]args) {
    // Initialize Scanner object
    Scanner sc = new Scanner (System.in);
    // Take user input
    System.out.print ("Enter the no. of students placed in CSE: ");
    int cse = sc.nextInt ();
    System.out.print ("Enter the no. of students placed in ECE: ");
    int ece = sc.nextInt ();
    System.out.print ("Enter the no. of students placed in MECH: ");
    int mech = sc.nextInt ();
    sc.close ();
    // If any integer is negative, print message and exit
    if (cse < 0 || ece < 0 || mech < 0){
	    System.out.println ("Input is Invalid");
        }
    // If all values are equal, print message and exit
    else{
	
       if (cse == ece && ece == mech && mech == cse){
	    System.out.println("None of the department has got the highest placement");
	  }
	//System.out.println("Highest Placement:");
    // First, check if any two values are equal and greater than the third
	  else if (cse == ece && cse > mech){
	    System.out.println ("Highest Placement:");
	    System.out.println ("CSE");
	    System.out.println ("ECE");
	  }
	else if (cse == mech && cse > ece){
	    System.out.println ("Highest Placement:");
	    System.out.println ("CSE");
	    System.out.println ("MECH");
	  }
	else if (ece == mech && ece > cse) {
	    System.out.println ("Highest Placement:");
	    System.out.println ("ECE");
	    System.out.println ("MECH");
	  }
	// Now, if we reached here, all values are distinct
    // Check if one value is greater than both
	  else if (cse > ece && cse > mech){
	    System.out.println ("Highest Placement:");
	    System.out.println ("CSE");
	  }
	else if (ece > mech){
	    System.out.println ("Highest Placement:");
	    System.out.println ("ECE");
	  }
	else{
	    System.out.println ("Highest Placement:");
	    System.out.println ("MECH");
	  }
      }
  }

}

Python

import sys
cse=int(input("Enter the no of students placed in CSE:"))

ece=int(input("Enter the no of students placed in ECE:"))

mech=int(input("Enter the no of students placed in MECH:"))

if(cse< 0 or ece< 0 or mech< 0):
    print("Input is Invalid")
    sys.exit()

elif(cse == ece and ece == mech ):
    print("None of the department has got the highest placement")

sys.exit()

print("Highest placement")

m=max(cse,ece,mech)

if(cse==m):
    print("CSE")

if(ece==m):
    print("ECE")

if(mech==m):
    print("MECH")

Question-5

Problem Statement – In a theater, there is a discount scheme announced where one gets a 10% discount on the total cost of tickets when there is a bulk booking of more than 20 tickets, and a discount of 2% on the total cost of tickets if a special coupon card is submitted. Develop a program to find the total cost as per the scheme. The cost of the k class ticket is Rs.75 and q class is Rs.150. Refreshments can also be opted by paying an additional of Rs. 50 per member.

Hint: k and q and You have to book minimum of 5 tickets and maximum of 40 at a time. If fails display “Minimum of 5 and Maximum of 40 Tickets”. If circle is given a value other than ‘k’ or ‘q’ the output should be “Invalid Input”.

The ticket cost should be printed exactly to two decimal places.

Sample Input 1:

Enter the no of ticket:35
Do you want refreshment:y
Do you have coupon code:y
Enter the circle:k

Sample Output 1:

Ticket cost:4065.25

Sample Input 2:

Enter the no of ticket:1

Sample Output 2:

Minimum of 5 and Maximum of 40 Tickets

C

Java

Python

C

Run

#include<stdio.h>
#include<stdlib.h>
int main () {
  
    int noTicket;
    double total = 0, cost;
    char ref[2], co[2], circle[2];
    printf ("Enter the no of ticket:");
    scanf ("%d", &noTicket);
    if (noTicket < 5 || noTicket > 40){
        printf ("Minimum of 5 and Maximum of 40 tickets");
        exit (0);
    }
    printf ("Do you want refreshment:");
    scanf ("%s", &ref);
    printf ("Do you have coupon code:");
    scanf ("%s", &co);
    printf ("Enter the circle:");
    scanf ("%s", &circle);
    if (circle[0] == 'k') cost = 75 * noTicket;
    else if (circle[0] == 'q') cost = 150 * noTicket;
    else {
        printf ("Invalid Input");
        exit (0);
    }
    total = cost;
    if (noTicket > 20)
    cost = cost - ((0.1) * cost);
    total = cost;
    if (co[0] == 'y')
    total = cost - ((0.02) * cost);
    if (ref[0] == 'y')
    total += (noTicket * 50);
    printf ("Ticket cost:%.2f", total);
  
    return 0;

}

Java

import java.util.Scanner;
import java.text.DecimalFormat;
public class Main 
{
  public static void main (String[]args) 
  {
        int noTicket;
        double total = 0, cost;
        String ref, co, circle;
        Scanner s = new Scanner (System.in);
        System.out.println ("Enter the no of ticket:");
        noTicket = s.nextInt ();
    
        if (noTicket < 5 || noTicket > 40){
	        System.out.println ("Minimum of 5 and Maximum of 40 tickets");
	        System.exit (0);
        }
        System.out.println ("Do you want refreshment:");
        ref = s.next ();
        System.out.println ("Do you have coupon code:");
        co = s.next ();
        System.out.println ("Enter the circle:");
        circle = s.next ();
        if (circle.charAt (0) == 'k') cost = 75 * noTicket;
        else if (circle.charAt (0) == 'q') cost = 150 * noTicket;
        else {
	
        System.out.println ("Invalid Input");
	    return;
      }
    
        total = cost;
        if (noTicket > 20)
        cost = cost - ((0.1) * cost);
        total = cost;
        if (co.charAt (0) == 'y')
        total = cost - ((0.02) * cost);
        if (ref.charAt (0) == 'y')
        total += (noTicket * 50);
        System.out.format ("Ticket cost:%.2f", total);
  
    }

}

}

Python

import sys
noTicket=int(input("Enter the no of ticket: "))

if (noTicket < 5 or noTicket > 40) :
    print("Minimum of 5 and Maximum of 40 tickets")
    sys.exit(0)

ref=input("Do you want refreshment: ")

co=input("Do you have coupon code: ")

circle=input("Enter the circle: ")

if(circle== 'k'):
    cost=75*noTicket

elif(circle== 'q'):
    cost=150*noTicket

else:
    print("Invalid Input")
    sys.exit(0)

total=cost

if(noTicket>20):
    cost= cost - ((0.1)*cost)
    total=cost

if(co== 'y'):
    total= cost - ((0.02)*cost)

if(ref== 'y'):
    total += (noTicket*50);

print("Ticket cost:{}".format(round(total,2)))

Question-6

Problem Statement – Rhea Pandey’s teacher has asked her to prepare well for the lesson on seasons. When her teacher tells a month, she needs to say the season corresponding to that month. Write a program to solve the above task.

Spring – March to May,
Summer – June to August,
Autumn – September to November and,
Winter – December to February.

Month should be in the range 1 to 12. If not the output should be “Invalid month”.

Sample Input 1:

Enter the month:11

Sample Output 1:

Season:Autumn

Sample Input 2:

Enter the month:13

Sample Output 2:

Invalid month

C

Java

Python

C

Run

#include<stdio.h>
#include<stdlib.h>
int main(){
    printf("Enter the month:");
    int entry ;
    scanf("%d",&entry);
    switch (entry) {
        case 12:
        case 1:
        case 2:
        printf("Season:Winter");
        break;
        case 3:
        case 4:
        case 5:
        printf("Season:Spring");
        break;
        case 6:
        case 7:
        case 8:
        printf("Season:Summer");
        break;
        case 9:
        case 10:
        case 11:
        printf("Season:Autumn");
        break;
        default:
        printf("Invalid month");
    }
    return 0;
}

Java

import java.util.Scanner;
public class Main {
  public static void main (String args[]) {
    
    System.out.print ("Enter the month:");
    Scanner s = new Scanner (System.in);
    int entry = s.nextInt ();
    switch (entry){
        case 12:
        case 1:
        case 2:
        System.out.println ("Season:Winter");
        break;
        case 3:
        case 4:
        case 5:
        System.out.println ("Season:Spring");
        break;
        case 6:
        case 7:
        case 8:
        System.out.println ("Season:Summer");
        break;
        case 9:
        case 10:
        case 11:
        System.out.println ("Season:Autumn");
        break;
        default:
        System.out.println ("Invalid month");
              
        }
   }
}

Python

mon=int(input("Enter month"))
if(mon==12 or mon==1 or mon==2):
    print("Season:Winter")

elif(mon==3 or mon==4 or mon==5):
    print("Season:Spring")

elif(mon==6 or mon==7 or mon==8):
    print("Season:Summer")

elif(mon==9 or mon==10 or mon==11):
    print("Season:Winter")

else:
    print("Invalid month")

Question-7

Problem Statement – To speed up his composition of generating unpredictable rhythms, Blue Bandit wants the list of prime numbers available in a range of numbers.Can you help him out?

Write a java program to print all prime numbers in the interval [a,b] (a and b, both inclusive).

Note

Input 1 should be lesser than Input 2. Both the inputs should be positive.
Range must always be greater than zero.
If any of the condition mentioned above fails, then display “Provide valid input”
Use a minimum of one for loop and one while loop

Sample Input 1:

2

15

Sample Output 1:

2 3 5 7 11 13

Sample Input 2:

8

5

Sample Output 2:

Provide valid input

C

Java

Python

C

Run

#include<stdio.h>
#include<stdlib.h>
int main () {
    int a, b;
    scanf ("%d%d", &a, &b);
    int flag;
    if (a <= 0 || b <= 0 || a >= b) printf ("Provide valid input");
    else{
        while (a <= b){
	  
            if (a == 2)
	            printf ("%d ", a);
	        else if (a == 1){
	            a++;
	            continue;
	        }
	        else{
	            flag = 0;
	            for (int i = 2; i <= a / 2; i++){
		            if (a % i == 0){
		                flag = 1;
		                break;
		            }
	                
	            }
	      
            if (flag == 0)  printf ("%d ", a);
	    
          }
          a++;
	    }
    }
    return 0;
}

Java

import java.util.*;
public class Main 
{
public static void main (String[] args) {

    Scanner sc=new Scanner(System.in);
    int a=sc.nextInt();
    int b=sc.nextInt();
    int flag;
    
    if(a<=0 || b<=0 || a>=b)
    System.out.println("Provide valid input");
    else{
        Inner:
        while(a<=b){
            if(a==2)
                System.out.print(a+" ");
            else if(a==1){
                a++;
                continue;
            }
            else{
                flag=0;
                outer:
                for(int i=2;i<=a/2;i++){
                    if(a%i==0){
                        flag=1;
                        break outer;
                    }
    
                }
    
            if(flag==0)
            System.out.print(a+" ");
        }
        a++;
        }
    }
    }
}

Python

a=int(input())

b=int(input())

if(a<=0 or b<=0 or a>=b):

    print("Provide valid input")

else:

    while(a<=b):

        if(a==2):

            print(a,end=" ");

        elif(a==1):

            a+=1

            continue            

        else:

            flag=0

            for i in range(2,a//2+1):

                if(a%i==0):

                    flag=1

                    break

            if flag==0:

                print(a,end=" ")         

        a+=1

Question-8

Problem Statement – Goutam and Tanul plays by telling numbers. Goutam says a number to Tanul. Tanul should first reverse the number and check if it is same as the original. If yes, Tanul should say “Palindrome”. If not, he should say “Not a Palindrome”. If the number is negative, print “Invalid Input”. Help Tanul by writing a program.

Sample Input 1 :

21212

Sample Output 1 :

Palindrome

Sample Input 2 :

6186

Sample Output 2 :

Not a Palindrome

C

Java

Python

C

Run

#include<stdio.h>
#include<stdlib.h>
int main(){
    int n ;
    scanf("%d",&n);
    int sum = 0, r;
    int temp = n;
    if(n>-1) {
        while(n>0){
            r = n % 10;
            sum = (sum*10)+r;
            n = n/10;
        }
    if(temp==sum)
        printf("Palindrome");
    else
        printf("Not a Palindrome");
    }
    else{
        printf("Invalid Input");
    }

    return 0;
}

Java

import java.util.Scanner;
public class Main
{
  public static void main (String args[])
  {
    Scanner in = new Scanner (System.in);
    int n = in.nextInt ();
    int sum = 0, r;
    int temp = n;

    if (n > -1)
      {
	while (n > 0)
	  {
	    r = n % 10;
	    sum = (sum * 10) + r;
	    n = n / 10;
	  }
	if (temp == sum)
	  System.out.println ("Palindrome");
	else
	  System.out.println ("Not a Palindrome");
      }
    else
      {
	System.out.println ("Invalid Input");
      }
  }
}

Python

n=input()
if(int(n)<0):
    print("Invalid Input")

elif(n==n[::-1]):
    print("Palindrome")

else:
    print("Not a Palindrome")

Question-9

XYZ Technologies is in the process of increment the salary of the employees. This increment is done based on their salary and their performance appraisal rating.

If the appraisal rating is between 1 and 3, the increment is 10% of the salary.
If the appraisal rating is between 3.1 and 4, the increment is 25% of the salary.
If the appraisal rating is between 4.1 and 5, the increment is 30% of the salary.

Help them to do this, by writing a program that displays the incremented salary. Write a class “IncrementCalculation.java” and write the main method in it.

Note : If either the salary is 0 or negative (or) if the appraisal rating is not in the range 1 to 5 (inclusive), then the output should be “Invalid Input”.

Sample Input 1 :

Enter the salary

8000

Enter the Performance appraisal rating

3

Sample Output 1 :

8800

Sample Input 2 :

Enter the salary

7500

Enter the Performance appraisal rating

4.3

Sample Output 2 :

9750

Sample Input 3 :

Enter the salary

-5000

Enter the Performance appraisal rating

6

Sample Output 3 :

Invalid Input

Java

C

Java

import java.util.*;
class Main{
public static void main (String[] args) {

Scanner sc = new Scanner (System.in);

System.out.println("Enter the salary");

int salary = sc.nextInt();

System.out.println("Enter the Performance appraisal rating");

float rating = sc.nextFloat();

if(salary<1||rating<1.0||rating>5.0){

System.out.println("Invalid Input");

System.exit(0);

}

else if(rating>=1&&rating<=3){ salary=salary+(int)(0.1*salary); System.out.println(salary); } else if(rating>3&&rating<=4){ salary=salary+(int)(0.25*salary); System.out.println(salary); } else /*if(rating>4&&rating<=5)*/{

salary=salary+(int)(0.3*salary);

System.out.println(salary);

}

}

}

C

#include<stdio.h>
#include<stlib.h>
int main ()
{
  printf ("Enter the salary");

  int salary;

  scanf ("%d", &salary);
  printf ("Enter the Performance appraisal rating");

  float rating;

  scanf ("%f", &rating);

  if (salary < 1 || rating < 1.0 || rating > 5.0)
    {

      printf ("Invalid Input");
      exit (0);

    }

  else if (rating >= 1 && rating <= 3) { salary = salary + (10 * salary / 100); printf ("%d", salary); } else if (rating > 3 && rating <= 4) { salary = salary + (25 * salary / 100); printf ("%d", salary); } else if (rating > 4 && rating <= 5)
    {

      salary = salary + (30 * salary / 100);

      printf ("%d ", salary);

    }

  return 0;

}

Question-10

Problem Statement – Chaman planned to choose a four digit lucky number for his car. His lucky numbers are 3,5 and 7. Help him find the number, whose sum is divisible by 3 or 5 or 7. Provide a valid car number, Fails to provide a valid input then display that number is not a valid car number.

Note : The input other than 4 digit positive number[includes negative and 0] is considered as invalid.

Refer the samples, to read and display the data.

Sample Input 1:

Enter the car no:1234

Sample Output 1:

Lucky Number

Sample Input 2:

Enter the car no:1214

Sample Output 2:

Sorry its not my lucky number

Sample Input 3:

Enter the car no:14

Sample Output 3:

14 is not a valid car number

Java

C++

Java

Run

import java.util.*;
class Main {
  public static void main (String[]args)
  {
        int sum = 0;
        Scanner sc = new Scanner (System.in);
        System.out.print ("Enter the car no:");
        int carNum = sc.nextInt ();
        if (carNum < 1000 || carNum > 9999)
        {
	        System.out.println (carNum + " is not a valid car number");
        }
        else
        {
            while (carNum != 0)
	        {
	            int l = carNum % 10;
	            sum = sum + l;
	            carNum = carNum / 10;
	        } 
 
       if (sum % 3 == 0 || sum % 5 == 0 || sum % 7 == 0)
	   {
	        System.out.println ("Lucky Number");
	   }
	   else
	   {
	        System.out.println ("Sorry its not my lucky number");
	   }
    }
  }

 
}

C++

#include <iostream>
#include<bits/stdc++.h>
using namespace std;
int main ()
{
    int n;
    cin >> n;
    int digit = floor (log10 (n) + 1);
    if (n <= 0 or ! (digit == 4)) cout << n << " is not a valid car number";
    else {
        int sum = 0;
        while (n > 0)
        {
            sum += n % 10;
            n /= 10;
        }

    if (sum % 3 == 0 or sum % 5 == 0 or sum % 7 == 0)
        cout << "Lucky Number";
    else
        cout << "Sorry its not my lucky number";
    }

    return 0;
}

Question-11

Problem Statement –

IIHM institution is offering a variety of courses to students. Students have a facility to check whether a particular course is available in the institution. Write a program to help the institution accomplish this task. If the number is less than or equal to zero display “Invalid Range”.

Assume maximum number of courses is 20.

Sample Input 1:

Enter no of course:

5

Enter course names:

Java

Oracle

C++

Mysql

Dotnet

Enter the course to be searched:

C++

Sample Output 1:

C++ course is available

Sample Input 2:

Enter no of course:

3

Enter course names:

Java

Oracle

Dotnet

Enter the course to be searched:

C++

Sample Output 2:

C++ course is not available

Sample Input 3:

Enter no of course:

0

Sample Output 3:

Invalid Range

Java

Python

C++

Java

Run

import java.util.*;
class Main
{
    public static void main(String[] args)
    {
        int n=0,flag=0;
        String courseSearch;
        Scanner sc = new Scanner (System.in);
        System.out.println("Enter no of course:");
        n= sc.nextInt();

        if(n<=0||n>20){
            System.out.println("Invalid Range");
            System.exit(0);
        }
        System.out.println("Enter course names:");
        String[] course = new String[n];
        sc.nextLine();
        for (int i = 0; i < course.length; i++) {
            course[i] = sc.nextLine();
        }
        System.out.println("Enter the course to be searched:");
        courseSearch=sc.nextLine();
        for (int i = 0; i < course.length; i++) {
            if(course[i].equals(courseSearch))
            {
                flag=1;
            }
        }

        if(flag==1){
            System.out.println(courseSearch+" course is available");
        }
        else {
            System.out.println(courseSearch+" course is not available");

        }

    }

}

Python

import sys
n = int(input("Enter no of course"))
if not (n >0 or n <20) :
    print("Invalid Range")
    exit()
course=[]
print("Enter the course names")
for i in range(n):
    course.append(input())
search = input("Enter the course to be searched")
if search in course:
    print(search ,"course is available ")
else:
    print(search,"course is not available")

C++

Run

#include<iostream>
#include<bits/stdc++.h>
using namespace std;
int main ()
{
    int n;
    cout << "Enter the number of courses: "; cin >> n;
    if (n <= 0 or n > 20)
        cout << "Invalid Range";
    else{
        vector < string > vec (n);
        map < string, int >mp;
        cout << "\nEnter courses names: ";
        for (int i = 0; i < n; i++)
        { 
            cin >> vec[i];
            mp[vec[i]]++;
        }
        string ser;
        cout << "\nEnter the course to be searched: "; cin >> ser;
        if (mp[ser] != 0)
        cout << "\n" << ser << " course is available.";
        else
        cout << "\n" << ser << " course is not available.";
    }

    return 0;

}

Question-12

Problem Statement – Mayuri buys “N” no of products from a shop. The shop offers a different percentage of discount on each item. She wants to know the item that has the minimum discount offer, so that she can avoid buying that and save money.
[Input Format: The first input refers to the no of items; the second input is the item name, price and discount percentage separated by comma(,)]
Assume the minimum discount offer is in the form of Integer.

Note: There can be more than one product with a minimum discount.

Sample Input 1:

4

mobile,10000,20

shoe,5000,10

watch,6000,15

laptop,35000,5

Sample Output 1:

shoe

Explanation: The discount on the mobile is 2000, the discount on the shoe is 500, the discount on the watch is 900 and the discount on the laptop is 1750. So the discount on the shoe is the minimum.

Sample Input 2:

4

Mobile,5000,10

shoe,5000,10

WATCH,5000,10

Laptop,5000,10

Sample Output 2:

Mobile

shoe

WATCH

Laptop

Java

Python

C++

Java

Run

import java.util.*;
import java.io.*;
public class Main{
    public static void main (String[] args) throws IOException{
        BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
        Scanner sc=new Scanner(System.in);
        int num = Integer.parseInt(br.readLine());
        int itemPrice[] = new int[num];
        int itemDis[] = new int[num];

        String itemName[] = new String[num];
        //String[] values;
        float dis[] = new float[num];
        String[] input = new String[num];
        for(int i=0;i< num;i++)
        {
            String s[]= br.readLine().split(",");
            itemName[i] =s[0];
            //System.out.println(itemName[i]);
            itemPrice[i]=Integer.parseInt(s[1]);
            // System.out.println(itemPrice[i]);
            itemDis[i]=Integer.parseInt(s[2]);
            // System.out.println(itemDis[i]);
            //float  x = itemDis[i]
            dis[i]=(float)((itemDis[i]*itemPrice[i])/100);
            // System.out.println(dis[i]);
        }

        int idx[]=new int[num];
        int j=0;
        float min= Float.MAX_VALUE;
        for(int i=0;i< num;i++){
            if(dis[i]<=min)
            {
                min=dis[i];
                idx[j++]=i;
                //System.out.println(min);
            }
        }
        for(int i=0;i< j;i++){
            System.out.println(itemName[idx[i]]);
            //System.out.println(idx[i]);
        }
    }

}

Python

items = int(input())
itemList=[]
for i in range(items):
    itemList.append(input().split(","))
list2=[]
for i in itemList:
    i.append((int(i[1])*int(i[2]))//100)
    list2.append(i[3])
result=[]  
minimum = min(list2)
for i in itemList:
    if i[3] == minimum:
        result.append(i[0])
for i in result:
    print(i)

C++

#include
#include
using namespace std;
int main ()v{
    int n;
    cin >> n;
    vector vec(n);
    for(int i=0; i< n; i++) cin>>vec[i];
    mapres;
    int mini=INT_MAX;
    for(int i=0; i< n;i++) {
        string temp ="";
        int num=0, per=0;
        int flag1=0, flag2=0;
        for(int j=0; j< vec[i].size(); j++)
        {
            if(vec[i][j]==',' and flag1==0)
                flag1=1;
            else if(vec[i][j]==',' and flag2==0)
                flag2=1;
            else if(vec[i][j]!=',' and flag1==0)
                temp += vec[i][j];
            else if(vec[i][j]!=',' and flag2==0)
                num = (num*10)+(vec[i][j]-'0');
            else
                per = (per*10)+(vec[i][j]-'0');
        }
        int dis = (num*per)/100;
        if(dis< mini)
        mini= dis;
        res[temp] = dis;

    }

    for(auto it=res.begin(); it!=res.end(); it++)
    {
        if(it->second==mini)
        cout<< first<< endl;
    }   
    return 0;
}

Question-13

Problem Statement – Raj wants to know the maximum marks scored by him in each semester. The mark should be between 0 to 100 ,if goes beyond the range display “You have entered invalid mark.”

Sample Input 1:

Enter no of semester:

3

Enter no of subjects in 1 semester:

3

Enter no of subjects in 2 semester:

4

Enter no of subjects in 3 semester:

2

Marks obtained in semester 1:

50
60
70

Marks obtained in semester 2:

90
98
76
67

Marks obtained in semester 3:

89
76

Sample Output 1:

Maximum mark in 1 semester:70
Maximum mark in 2 semester:98
Maximum mark in 3 semester:89

Sample Input 2:

Enter no of semester:

3

Enter no of subjects in 1 semester:

3

Enter no of subjects in 2 semester:

4

Enter no of subjects in 3 semester:

2

Marks obtained in semester 1:

55
67
98

Marks obtained in semester 2:

67
-98

Sample Output 2:

You have entered invalid mark.

Java

Python

C++

Java

import java.util.*;
import java.lang.*;
import java.io.*;
class Main{
    public static void main (String[] args) throws java.lang.Exception{
        Scanner sc = new Scanner (System.in);
        System.out.println("Enter no of semester:");
        int sems = sc.nextInt();
        boolean incorrect = false;
        int arr[] = new int [sems];
                
        for(int i=0;i< sems;i++) {
            System.out.println("Enter no of subjects in "+(i+1)+" semester:");
            arr[i]=sc.nextInt();
        }
        int maxMarks[] = new int[sems];
        for(int i=0;i< sems;i++) {
            System.out.println("Marks obtained in semester "+(i+1)+":");
            int max = sc.nextInt();
            if(max<0||max>100) {
                System.out.println("You have entered invalid mark.");
                System.exit(0);
            }
        for(int j=1;j< arr[i];j++) {
                int marks=sc.nextInt();
                if(marks<0||marks>100)
                {
                    System.out.println("You have entered invalid mark.");
                    System.exit(0);
                }

                if(max< marks)
                max=marks;
            
        }
        maxMarks[i]= max;
    }
    for(int i=0;i< sems;i++) {
        System.out.println("Maximum mark in "+(i+1)+" semester:"+maxMarks[i]);
    }

}

}

Python

no_of_sem =  int( input("Enter the no of sem"))
list1=list()
for i in range(no_of_sem):
    print("Enter the no of subjects in sem",i+1)
    list1.append(list(range(int(input()))))
for i in range(no_of_sem):
    print("Marks obtained in sem ",i+1)
    for j in range(len(list1[i])):
        list1[i][j]=int(input())
        if not list1[i][j] in range(0,101):
            print("You have Entered Invalid Marks")
            exit()
count = 1
for i in list1:
    print("Maximum marks in ", count," sem:",max(i))
    count+=1

C++

#include<iostream>
using namespace std;
int main ()
{

int n;

cout << "Enter the number of semester: ";
cin >> n;

vector < int >sem (n);

for (int i = 0; i < n; i++)
{

cout << "\nEnter number of subjects in " << i + 1 << " semester :";
cin >> sem[i];

}

for (int i = 0; i < n; i++)
{
cout << "\nMarks obtained in " << i + 1 << " semester :";

int maxi = 0, mark;

while (sem[i]--)
{
cin >> mark;

if(!(mark <= 100 and mark >= 0))
{
cout << "\nYou have entered invalid marks.";
goto r;
}

maxi = max (maxi, mark);
}

cout << "\nMaximum mark in " << i + 1 << " semester :" << maxi;

}

r: return 0;
}

Question-14

Problem Statement – Bela teaches her daughter to find the factors of a given number. When she provides a number to her daughter, she should tell the factors of that number. Help her to do this, by writing a program. Write a class FindFactor.java and write the main method in it.
Note :

If the input provided is negative, ignore the sign and provide the output. If the input is zero
If the input is zero the output should be “No Factors”.

Sample Input 1 :

54

Sample Output 1 :

1, 2, 3, 6, 9, 18, 27, 54

Sample Input 2 :

-1869

Sample Output 2 :

1, 3, 7, 21, 89, 267, 623, 1869

Java

Python

C++

Java

import java.util.*;
public class Main{
public static void main(String[] args){
    int i;
    Scanner sc = new Scanner (System.in);
    int num = sc.nextInt();
    if(num==0){
        System.out.println("No Factors");
    }
    else if(num>0){
        for(i=1;i< num;i++){
            if(num%i==0){
                System.out.print(i+", ");
            }
        }
        System.out.println(num);
    }
    else{
        num=num*-1;
        for(i=1;i< num;i++){
            if(num%i==0){
                System.out.print(i+", ");
            }
        }
    System.out.println(num);
    }

}

}

Python

x = abs(int(input()))
if x == 0:
    print("No Factors")
    exit()
for i in range(1, x + 1):
    if x % i == 0:
        if i != x:
            print(i,end=", ")
        else:
            print(i)

C++

#include<iostream>
#include<bits/stdc++.h>
using namespace std;
int main ()
{
    int n;
    cin >> n;
    n = abs (n);
    if (n == 0) cout << "No factors";
    else {
        for (int i = 1; i < n; i++) {
            if (n % i == 0) cout << i << ",";
        }

        cout << n;
    }
    return 0;
}

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