TCS Digital Ages Quiz – 1

At present

Age of Umesh = x

Age of Reena is Y age of Mahesh is m

after 6 years

X+6=4(y+6)

X+6=4y+24

But it is given that age of Mahesh is equal to 7 times age of Reena

So

7y+6=4y+24

3y+6=24

3y=18

Y=6

Age of Mahesh is equal to 7 times the age of Reena

X=7 x 6

=42



Video solution:

Total Age of 10 students and Teacher = 11 x 15 = 165

Total age of first 7 students = 7 x 15 = 105

Total age of 3 students = 3 x 11 = 33

Thus total age of students = 33 + 105 = 138

Age of Teacher = 165 - 138 = 27



Video solution:

Since its 13 years ago

Nina's 13 year ago age = Present age - 13 = 37 - 13 = 24

Aman 13 year ago age = Present age - 13 = 59 - 13 = 46

Ratio = \frac{24}{46} = 12:23



Video solution:

4 Years Back,
Average age of the family = 19 years
Sum or Total of all ages of all 4 family members = 19 x 4 = 76 Years.

In Present Day, that means after 4 years
Sum or total of present ages of these 4 family members = 76 + (4 + 4) = 92 Years

Let the child’s present age be K years old.
Now the family is of 5 members (because the child was added few years back)

Present Average age of family =
\frac{\text{Sum of present ages of 4 members + Child's Present age}}{5}

Average remains the same as it was 4 years back.
\therefore 19 = \frac{92 + K}{5}
\therefore K = 3​ years (The present age of child)



Video solution:

After K years,

\frac{\text{B's age}}{\text{A's age}} = \frac{\text{Present age of B + K}}{\text{Present age of A + K}} = \frac{36 + K}{42 + K} = \frac{15}{17}

∴ 17(36 + K) = 14(42 + K)

∴ K = 9



Video solution:

Total present age of the friend group = (4x36) = 144 years

Total age of the friend 6 years ago = (144-6x4) = 120 years

At that time, the number of member = 3

Therefore Average age at that time = \frac{120}{3} = 40 years



Video solution:

Let present age of Amit and dhiraj be 5x and 4x.

After 6 years age of Amit=(5x+6).

According to question,

5x + 6 = 26

5x = 20

x = 4 years.

Present age of dhiraj = 4x = 16 years.



Video solution:

Explanation:
Let the ages of husband and wife at the time of their 20th wedding anniversary be X years and Y years respectively and X > Y.
Their combined age = (X + Y) years.
The ages of both husband and wife at the time of wedding will be (X – 20) years and (Y – 20) years respectively.
Their combined age = (X – 20) + (Y – 20)
= (X + Y – 40) Years
By first information, we have
(X + Y) = 2( X + Y – 40)
X + Y = 2X + 2Y - 80
Therefore, X + Y = 80-------A
and by second information, we have
X – Y =3 ----------------------B
Solving A and B, we get X = 41.5 years
Therefore, the age of husband at the time of their 20th wedding anniversary X = 41.5 years
Age at the time of marriage = 41.5 years – 20 years = 21.5 years.



Video solution:

Let Neha's present age be 'x' years.
Her age 12 years ago = (x – 12) years
Therefore, her mother's age 12 years ago = 4(x – 12)
Her mother's present age = 4x – 48 + 12 = 4x – 36
Neha's age after 12 years = x + 12
Her mother's age after 12 years = 4x – 36 + 12 = 4x – 24
4x – 24 = 2(x + 12)
4x – 2x = 24 + 24
x = 24
Therefore, Neha's present age = 24
Her mother's present age = 4x – 36 = 4(24) – 36 = 60 years



Video solution: