Mu Sigma Flowcharts Quiz-1

Option(A) Explanation

According to condition 1 the number in box 11 changes. Condition 1 is to add number in box 3 and number in box 11. 0 + 1 = 1 The new number in box 11 at the end of the flowchart is 1.

Option(A) Explanation

According to the conditions given in the flowchart the loop between 6 to 3 is repeated 3 times to get the number in box 5 and 10 equal.

Option(B) Explanation

According to the flowchart and the conditions given in it, no changes are done in box 12. Therefore, at th4e end of the flowchart the number in box 12 remains same as given.

Option(C) Explanation

According to the flowchart and the conditions given in it the number in box 6 = number in box 4 + number in box 8. The number in box 4 is ‘9’ and the number in box 8 is ’18.’ On adding we get 27 as number in box 4. Number in box 2 is 2. Therefore, 27 + 2 = 29.

 

Option(A) Explanation

In 1 st condition we have to subtract the value in box 4 with value in box 10. 5-2 = 3

In condition 2 nd we have to add the value in box with the value in box 6. 3 + 3 = 6.

Therefore, 6 is not evenly divisible by 4. Thus condition 3 is not true.

Option(B) Explanation

According to the flowchart and the conditions given in it, the number in box 5 remain unchanged.

Option(B) Explanation

According to the flowchart and the instructions given in it, only the number in box 1 and box 9 changes.

All other boxes remains unchanged.

Therefore, 15 -2 = 13. Thus, 13 boxes remain unchanged.

Option(A) Explanation The number in box 9 at the end of the flowchart is 6 (in the last instruction it is mentioned to subtract the number in box 9 by 1 and put the value in box 9). The number in box 9 = 7 7 – 1 = 6 Therefore number in box 9 is 6 The number in box 10 at the end of the flowchart is 2. Thus, 6 is greater than 2.

Option(A) Explanation According to the 1 st instruction put the number of box 8 in box 1 Box 8 = 0 Therefore Box 1 = 0. According to the 2 nd instruction add number in box 2 and number in box 1 Number in box 2 = 7 Number in box 1 = 0 7 + 0 = 7 Therefore, number in box 1 = 7.

Option(B) Explanation According to the instruction 3, we have to increase the number in Box 2 by 1. Therefore, number in box 2 = 7 7 + 1 = 8 Number in box 2 = 8 Number in box 6 = 12 Thus, number in box 2 in not greater than number in box 6