Table Chart Questions and Answers Quiz-3

Solution:

Total number of failures in half-yearly exams in a section

= [ (Number of students who failed in both exams) + (Number of students who failed in half-yearly but passed in Annual exams) ] in that section

The failure rate in half-yearly exams in Section A %= 37.5 %

Similarly, the failure rate in half-yearly exams in:

Section B = 32.71%

Section C = 31.25%

Section D = 30.53%

Clearly, the failure rate is minimum for Section D.

 

Solution:

Required difference

= (272 + 240 + 236 + 256 + 288) - (200 + 224 + 248 + 272 + 260)

= 88.

Solution:

Total number of Peons working in the Company in 2019

= (820 + 184 + 152 + 196 + 224) - (96 + 88 + 80 + 120) = 1192.

Solution:

Number of Managers working in the Company:

In 2015 = 760.

In 2020 = (760 + 280 + 179 + 148 + 160 + 193) - (120 + 92 + 88 + 72 + 96)= 1252.

Therefore, the Percentage increase in the number of Managers

=\frac{(1252−760)}{760}\times 100\%= 64.74\%

 

Number of Technicians working in the Company:

In 2015 = 1200.

In 2020 = (1200 + 272 + 240 + 236 + 256 + 288) - (120 + 128 + 96 + 100 +112) = 1936.

Therefore, the Percentage increase in the number of Technicians

=\frac{(1936−1200)}{1200}\times 100\% = 61.33\%

 

Number of Operators working in the Company:

In 2015 = 880.

In 2020 = (880 + 256 + 240 + 208 + 192 + 248) -  (104 + 120 + 100 + 112 + 144) = 1444.

Therefore, the Percentage increase in the number of Operators

=\frac{(1444−880)}{880}\times 100\% = 64.09\%

 

Number of Accountants working in the Company:

In 2015 = 1160.

In 2020 = (1160 + 200 + 224 + 248 + 272 + 260) -  (100 + 104 + 96 + 88 + 92) = 1884.

Therefore, the Percentage increase in the number of Accountants

=\frac{(1884−1160)}{1160}\times 100\% = 62.14\%

 

Number of Peons working in the Company:

In 2015 = 820.

In 2020 = (820 + 184 + 152 + 196 + 224 + 200) - (96 + 88 + 80 + 120 + 104) = 1288.

Therefore, the Percentage increase in the number of Peons

=\frac{(1288−820)}{820}\times 100\% = 57.07\%

 

Clearly, the percentage increase is maximum in the case of Managers.

 

Solution:

Total number of employees of various categories working in the Company in 2017 are:

Managers = (760 + 280 + 179) - (120 + 92) = 1007.

Technicians = (1200 + 272 + 240) - (120 + 128) = 1464.

Operators = (880 + 256 + 240) - (104 + 120) = 1152.

Accountants = (1160 + 200 + 224) - (100 + 104) = 1380.

Peons = (820 + 184 + 152) - (96 + 88) = 972.

Therefore, Pooled average of all the five categories of employees working in the Company in 1997 =\frac {1}{5} \times (1007 + 1464 + 1152 + 1380 + 972)

= \frac{1}{5} \times (5975)

= 1195.

Solution:

 Required percentage = \left [ \frac{(720 + 840 + 780 + 950 + 870)}{(980 + 1050 + 1020 + 1240 + 940)}\times 100 \right ]\%

= \left [ \frac{4160}{5230}\times 100 \right ]\%

= 79.54% ~= 80%.

Solution:

Required average

=\frac{8100 + 9500 + 8700 + 9700 + 8950}{5}

=\frac{44950}{5}

= 8990.

Solution:

Required percentage

= \left [\frac{(850 + 920 + 890 + 980 + 1350)}{(7400 + 8450 + 7800 + 8700 + 9800)}\times 100 \right ]\%

=  \left [ \frac{4990}{42150}\times 100 \right ]\%

= 11.84%.

Solution:

Required percentage = \left [ \frac{(1020 + 1240)}{(8800 + 9500)}\times 100 \right ]\%

= \left [ \frac{2260}}{18300}\times 100 \right ]\%

= 12.35%.

Solution:

The percentages of candidates qualified to candidates appeared from Maharashtra during different years are:

For 2015 = \left ( \frac{780}{6400}\times 100 \right )\% = 12.19\%

For 2016 = \left( \frac{1020}{8800}\times 100 \right )\% = 11.59\%.

For 2017 = \left( \frac{890}{7800}\times 100 \right )\% = 11.41\%.

For 2018 = \left( \frac{1010}{8750}\times 100 \right )\% = 11.54\%

For 2019 = \left( \frac{1250}{ 9750}\times 100 \right )\% = 12.82\%

 

Therefore the Maximum percentage is for the year 2019.