Two Trains and a Flying Bird Puzzle
Puzzle of Two Trains and a Flying Bird
Premise – The puzzle of Two trains and a flying bird are at points A and B respectively. They have a distance of 120km between them. A bird is sitting on top of the train at point A. The trains start moving towards each other at a constant speed of 60 km/hr.
Rule – When the train starts, the bird also starts flying toward the other train, at a speed of 200km/hr. When it reaches the train it turns back and flies towards the first train and repeats the step over and over till both the trains collide.
Objective – How much distance does the bird cover?
Solution for the Puzzle
Speed of Train A=60km/hr
Speed of Train B =60km/hr
Since both trains are moving towards each other, their relative speed will be
Relative speed = Speed of Train A + Speed of Train B
= 60 + 60 = 120 km/hr
Therefore time in which the trains will collide with each other=\frac{Distance \:between \:the \:trains}{Relative \: Speed \: of A \: and \: B}
=\frac{120\:km}{120\: km/hr}
= 1 hr
Hence both trains will collide with each other after 1 hour.
Now according to the question, we need to find the distance the bird travels before both the trains collide.
We know the bird is flying at a constant speed of 200km/hr
The distance the bird travels within that time will be = time taken for collision * speed of the bird
= 1 hr * 200 km/hr
= 200km
Hence the bird will cover a distance of 200 km while flying back and forth between the two trains before they collide.
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