Maximum Runs in Cricket Puzzle

Maximum Runs in Cricket

Solve the Puzzle: Maximum Runs in Cricket

In Maximum Runs in Cricket Puzzle, we have one day international cricket match. In a one day international cricket match, considering no extras(no wide, no ‘no’ balls, etc.) and no overthrows. What is the maximum number of runs that a batsman can score in an ideal case ?

Note :  Here we assume an ideal and little practical scenario. We assume that a batsman can not run for more than 3 runs in a ball, as otherwise there is no limit, he can run infinite runs(theoretically) in a ball, as far as the opposite team does not catch the ball.

Maximum Runs in Cricket

Solve the Puzzle: Maximum Runs in Cricket

In Maximum Runs in Cricket Puzzle, we have one day international cricket match. In a one day international cricket match, considering no extras(no wide, no ‘no’ balls, etc.) and no overthrows. What is the maximum number of runs that a batsman can score in an ideal case ?

Note :  Here we assume an ideal and little practical scenario. We assume that a batsman can not run for more than 3 runs in a ball, as otherwise there is no limit, he can run infinite runs(theoretically) in a ball, as far as the opposite team does not catch the ball.

Solution

In a one day international cricket match

  Here we have solution for Maximum Runs in Cricket Puzzle – 

  From Over 1 to 49:

  In singe over we get –

  • In 1st ball we get :- 6 runs (hit six)
  • In 2nd ball we get :- 6 runs (hit six)
  • In 3rd ball we get :- 6 runs (hit six)
  • In 4th ball we get :- 6 runs (hit six)
  • In 5th ball we get :- 6 runs (hit six)
  • In 6th ball we get :- 3 runs (took 3 runs between the wickets and take back the strike)

   Therefore, Total Run in 49 overs will be =  49*(6*5+3)

   Now in 50th Over : Hit six sixes in a row, so total runs will be –

   49*(6*5+3)+(6*6)= 1653

Solution

  Here we have solution for Maximum Runs in Cricket Puzzle – 

  From Over 1 to 49:

  In singe over we get –

  • In 1st ball we get :- 6 runs (hit six)
  • In 2nd ball we get :- 6 runs (hit six)
  • In 3rd ball we get :- 6 runs (hit six)
  • In 4th ball we get :- 6 runs (hit six)
  • In 5th ball we get :- 6 runs (hit six)
  • In 6th ball we get :- 3 runs (took 3 runs between the wickets and take back the strike)

   Therefore, Total Run in 49 overs will be =  49*(6*5+3)

   Now in 50th Over : Hit six sixes in a row, so total runs will be –

   49*(6*5+3)+(6*6)= 1653

In a one day international cricket match

For more, practice the following puzzles :-

the worm and leaves puzzle

For more, practice the following puzzles :-

the worm and leaves puzzle