# Maximum Runs in Cricket Puzzle

## Solution

Here we have the solution for Maximum Runs in Cricket Puzzle –

From Over 1 to 49:

In singe over we get –

• In 1st ball, we get :- 6 runs (hit six)
• In 2nd ball, we get :- 6 runs (hit six)
• In 3rd ball, we get :- 6 runs (hit six)
• In the 4th ball we get:- 6 runs (hit six)
• In the 5th ball we get:- 6 runs (hit six)
• In the 6th ball we get:- 3 runs (took 3 runs between the wickets and take back the strike)

Therefore, Total Run in 49 overs will be = 49*(6*5+3)

Now in 50th Over: Hit six sixes in a row, so total runs will be – 49*(6*5+3)+(6*6)= 1653

## Solve the Puzzle: Maximum Runs in Cricket

In Maximum Runs in Cricket Puzzle, we have a one-day international cricket match. In a one-day international cricket match, considering no extras(no wide, no ‘no’ balls, etc.) and no overthrows. What is the maximum number of runs that a batsman can score in an ideal case?

Note: Here we assume an ideal and little practical scenario. We assume that a batsman can not run for more than 3 runs in a ball, as otherwise there is no limit, he can run infinite runs(theoretically) in a ball, as far as the opposite team does not catch the ball.

### Solution

Here we have the solution for Maximum Runs in Cricket Puzzle –

From Over 1 to 49:

In singe over we get –

• In 1st ball, we get :- 6 runs (hit six)
• In 2nd ball, we get :- 6 runs (hit six)
• In 3rd ball, we get :- 6 runs (hit six)
• In the 4th ball we get:- 6 runs (hit six)
• In the 5th ball we get:- 6 runs (hit six)
• In the 6th ball we get:- 3 runs (took 3 runs between the wickets and take back the strike)

Therefore, Total Run in 49 overs will be = 49*(6*5+3)

Now in 50th Over: Hit six sixes in a row, so total runs will be –

49*(6*5+3)+(6*6)= 1653

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