TCS Digital Number Series Quiz-2

Text solution:
The given numbers are in AP with common difference d=111,Therefore to get next term we should add 45 i.e. 468+111=579.



Video solution:

Text solution:
Given series 23,68,113,158,203
68-23=45
113-68=45
158-113=45
203-158=45
The difference of these numbers is in AP with common difference d=45,Therefore to get next term we should add 45 i.e. 203+45=248.



Video solution:

Text solution:
3 * 4 = 12

12*4 = 48

48*4 = 192

192*4 = 768

768*4 =  3072



Video solution:

Text solution:
256 64 128 32 64 . there are 2 series alternatively.
256, 128,64 are a series
64 , 32,... are another series.
each series is formed by dividing the terms by 2. 256/2 = 128, 128/2= 64 ... similarly for second series also 64/2 =32, 32/2=16



Video solution:

Text solution:
4*6=24
4*12=48
4*18=72
4*24=96
4*30=120



Video solution:

Text solution:
Given series 2,6,30,210 ..
This can be interpreted as

• 2*3=6


• 6*5=30


• 30*7=210


• 210*9=1890

Only one pattern follows here, there is one letter difference b/w first two letter and the last letter is 2 letters before the last 2 letter of alphabetical series.

FHX- One letter difference b/w F and H and and  X is before last two letter of alphabetical series

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