Python program for octal to decimal conversion
Octal To Decimal Conversion
Here, in this page we will discuss the program for octal to decimal conversion in python . Octal numbers are also called numbers with base 8 and hold values from 0 – 7. Whereas in Decimal numbers are with base 10 is Standard number system for denoting integers and non-integers.
Methods discussed:
- Algorithmic way (Octal to Decimal)
- Inbuilt Method (Octal to Decimal)
Method 1 : Algorithmic Way
Algorithm :
- Initialize two variable decimal value and base 0, 1 respectively
- Iterate using while loop until num is greater then 0
- For each iteration het the unit place digit and multiply it with base and add it to decimal value
- divide num by 10 and multiply base with 8
Python Code :
Run
def OctalToDecimal(num): decimal_value = 0 base = 1 while num: last_digit = num % 10 num = int(num / 10) decimal_value += last_digit * base base = base * 8 return decimal_value octal = 512 print("The decimal value of",octal, " is",OctalToDecimal(octal))
Output :
The decimal value of 512 is 330
Method 2 : Inbuilt Method
By using inbuilt function int in Python we can convert any number with any base to decimal.Python Code
Run
octal_num = 512 decimal_value = int(str(octal_num), 8) print("The decimal value of {} is {}".format(octal_num, decimal_value))
Output
The decimal value of 512 is 330
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n=int(input())
l=list(str(n))
l.reverse()
decimal=0
for i in range(0,len(l)):
decimal+=int(l[i])*pow(8,i)
print(decimal)
num=int(input(“Enter the octal number “))
temp=num
deci_val=0
base=1
while(temp):
digit=temp%10
deci_val+=digit*base
base*=8
temp//=10
print(“The decimal value of {} is {}”.format(num,deci_val))
num_string=input()
nums=[]
for i in num_string:
if i.isdigit():
i=int(i)
nums.append(i)
length=len(nums)
nums=nums[::-1]
sums=0
for i in range(0,length):
nu=nums[i]
nu=int(nu)
result=nu*(8**(i))
sums=sums+result
print(sums)