Mettl Ages Quiz 1

Sister = x; Brother = x+2; Father = 29+x+2; Mother = 25+x
Present age – 4x+58
After 6 years
4x+58+30 = 4x+88
4x+88 = 100
x = 3
Mothers age = 25+x = 28.

(x-10) = 2/5 (y-10)
(x+10) = 3/5 (y+10)
Solve, x = 26 and y = 50
Difference = 50 - 26 = 24 years

M/D = 6/7
A- M =7
A+8 = 51 A = 43
M = 36
D = 42
D-M = 42-36 = 6

Sum of the present age of A and B = 2 × (6x – 15) = 12x – 30 years
Sum of the present age of A, B and C = 3 × (4x + 6) = 12x + 18 years
So, the present age of C = 12x + 18 – 12x + 30 = 48 years
Present age of B = 48 × 0.75 = 36 years
Present Age of A is \frac{30}{1.2} = 30Years

Let the age of Abhimanyu at their silver anniversary = K yrs
18 yrs of marriage = 7 yrs before the silver anniversary
Age of Abhimanyu 7yrs before silver anniversary = K – 7
Abhimanyu’s age 25 yrs after silver anniversary (golden anniversary) = K + 25
\frac{K - 7}{K + 25} = \frac{5}{21}
K = 17yrs
Seema’s age on silver anniversary = 17yrs
She is born 25 – 17 yrs = 8yrs after the marriage.

2S+F = 79
2F+S = 104
S =18, F = 43
18+43+M/3 = 32
M =35

Let, the present average age of the group = X
Then according to the question,
\frac{150}{100}(X-5) = X
X = 15
The required average ‘Y’ = \frac{15\times 60+ 22+ 38}{62}= 15.48

Let Ananya’s age = A, Bhavna’s age = B, and Charan’s age = C
Then, according to the question,
\frac{A}{C} = \frac{3}{4}.....(i)
\frac{B+5}{C-1} = \frac{4}{3}.......(ii)
4 x (C - A) = (B + 1)......(iii)
After solving these equations,
⇒ A = 12
⇒ C = 16
Average of ages of Amon and Chan =\frac{12 + 16}{2}= 14

Present age of daughter = 8 years
Age of Mother and Daughter 4 years back = 36 and 4 respectively
Present age of Mother = 40 years
Present age of Son = 15 years
Age of Father and Mother when son was born( 15 years back) = 30 and 25 respectively.
Therefore, present age of father = 45 years
Age of family 8 years ago
Daughter = 0
Son = 7
Mother = 32
Father = 37
Average age = \frac{7+ 32+ 37 }{3}= 25.33 years

Elephant was 5 times older than Giraffe 10 years ago.
Let the age of Giraffe 10 years ago be x years.
∴ The age of Elephant 10 years ago = 5x years
5 years from now, Elephant will be twice older than Giraffe.
∴ We can write now,
(5x + 10 + 5) = 2 × (x + 10 + 5)
⇒ 5x + 15 = 2x + 30
⇒ 3x = 15
⇒ x = 5
∴ Age of Giraffe 10 years ago = 5 years
And, the age of Elephant 10 years ago = 5x = 5 × 5 = 25 years
Therefore the required ratio
\frac{25+5}{5+5} = \frac{30}{10} = 3:1