Quiz-1

Clearly, the narrator starts from A, moves towards north-east a distance of 10 m up to B, turns left (90 degree anti-clockwise) and moves 7.5 m up to C. Clearly, C lies to the north of A. Also , ΔABC is right-angled at B. So,
AC^{2}= AB^{2}+ BC^{2}= (10)^{2}+ (7.5)^{2}
= 100 + 56.25 = 156.25
AC = \sqrt{156.25m} = 12.5m
Thus the narrator is 12.5 m to the north of his initial position.

Clearly, Rajesh starts from home at A, moves 10 km south wards up to B, turns right and moves and 5 km up to C, turns right again and moves 10 km up to D and finally turns left and moves 10 km up to E.
Thus his distance from initial position
A = AE + DE = BC + DE = (5 + 10) km = 15 km

Clearly, Kate Bush moves from A 10 km north-wards up to B, then moves 6 km southwards up to C, turns towards East and walks 3 km up to D. Then, AC = (AB - BC) = (10 – 6) = 4 km. So, Kate’s distance from the starting point A.
AD = \sqrt{( AC^{2} + CD^{2})} = 4^{2} + 3^{2} = 5 km
Also, D is to the North-east of A.

Its clear from the diagram that Ravina is facing East.

So, the total distance from the intial position = 15 m + 10 m = 25 m

It is clear from the diagram that now Sridevi is facing North

Let Adiik,Birla,Chinki and Diksha be denoted as A,B,C and D.


Its clear from the diagram that Diksha is SE of Chinki.

Its clear from the diagram that Jim’s distance
= 20 m + 40 m = 60 m.

She is going to West right now.