AMDOCS Coding Deductive Logic Quiz-1

Answer: Option 'C'

Clearly,
T -1 = S
A -1 = Z
P -1 = O
So FREEZE will be,

F -1 E R -1 Q
E -1 D
E -1 D
Z -1 Y
E -1 D

Answer: Option 'B'

Clearly every letter is increased by 1 as
M +1 N
A +1 B
D +1 E
R +1 S
A +1 B
S +1 T
So after increasing every character in work BOMBAY by 1, we get

Answer: Option 'D'

Each letter of the word is moved four step back to decode it.
So GEORGE will be CAKNCA

Answer: Option 'A'

Clearly every letter is decreased by 1.
So DISPOSE will be CHRONRD

Answer: Option 'D'

Answer: Option 'D'
In given word, word is increasing and decreasing by one alternatively as,
S +1 T
I -1 H
K +1 L
K -1 J
I +1 J
M -1 L
So in the same way TRAINING will be UQBHOHOF

Answer: Option 'C'

PRIVATE --> 1234567
RISK --> 2398 RIVETS --> 2 3 4 7 6 9

Answer: Option 'C'

There are 8 letters in word.
The first letter of the word has been left intact.
The order of remaining letters has been reversed.

Answer: Option 'B'

There are 7 letters in the word.
The middle letter (4th) has been left intact.
The first and the last letters of the word have interchanged their position.
Similarly, the second and the thisrd letters and he fifth and the sixth letters have
interchanged their position.

Answer: Option 'C'

There are 8 letters in the word.
In the given code the fourth and the eighth letters from left have been left intact.
The first letter exchanges position with the seventh letter, the second letter with
the sixth letter and the third with the fifth letter..

Answer: Option 'B'

In the given code, the letters of even numbered position have been left as they as they are while the first and the third letters have been interchanged. Similarly, the fifth and the seventh letters have been interchanged.