Octal to binary conversion using Java

October 14, 2022

Octal to Binary Conversion using Java

Here, on this page, we will discuss octal to binary conversion using java. For this purpose, we need to ask for an octal number from user and convert that octal number to its binary equivalent form and then print the converted number onto the screen.

For conversion, we first convert the octal number into decimal form and then convert the decimal number to a binary number.

Octal to binary conversion using java

Method 1:-

  • Accept octal number
  • Convert it into decimal Equivalent
  • Convert this decimal value into Binary

Make sure you have visited these two pages before moving ahead with the code –

Method 1 Code in Java

Run 
//Java program to convert octal number to binary number
class Main
{
    public static void main(String args[])
    {
        int octal = 12;

        //Declaring variable to store decimal number
        int decimal = 0;
        //Declaring variable to use in power
        int n = 0;

        //writing logic for the octal to decimal conversion
        while(octal > 0)
        {
            int temp = octal % 10;
            decimal += temp * Math.pow(8, n);
            octal = octal/10;
            n++;
        }

        int binary[] = new int[20];
        int i = 0;

        //writing logic for the decimal to binary conversion
        while(decimal > 0)
        {
            int r = decimal % 2;
            binary[i++] = r;
            decimal = decimal/2;
        }

        //printing result
        System.out.print("Binary number : ");

        for(int j = i-1 ; j >= 0 ; j--)
            System.out.print(binary[j]+"");

    }
}

Output

Enter a octal number : 12
Binary number : 1010

Decimal to Binary conversion

Decimal to Octal Conversion

Decimal to Hexadecimal Conversion

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Octal to Binary conversion

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Method 2

Each digit of an octal number can be converted into its binary Equivalent (see image)

Binary Representation for Octal digit:

  • 0 => 000
  • 1 => 001
  • 2 => 010
  • 3 => 011
  • 4 => 100
  • 5 => 101
  • 6 => 110
  • 7 => 111
Octal to binary conversion using java
Octal to Binary in Java

Method 2 Code in Java:

Run 
import java.util.HashMap;
class Main
{
    public static void main(String[] args)
    {
        HashMap b =new HashMap();
        b.put(0,"000");
        b.put(1,"001");
        b.put(2,"010");
        b.put(3,"011");
        b.put(4,"100");
        b.put(5,"101");
        b.put(6,"110");
        b.put(7,"111");

        String result =" ";
        long num = 347;
        long n=num;
        while(n !=0)
        {
            int rem=0;
            rem=(int)n%10;
            if(n!=0)
            {
                result = b.get(rem)+result;

            }
            n=n/10;

        }
        System.out.println(result);
    }
}

Output

Enter a octal number : 347
Binary number : 011100111

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4 comments on “Octal to binary conversion using Java”


  • pjanhabi584

    import java.util.*;
    public class Octal_Binary
    {
    public static void main(String args[])
    {
    Scanner sc=new Scanner(System.in);
    System.out.println(“Enter an octal number : “);
    int num=Integer.parseInt(sc.nextLine(),8);
    String Binary=Integer.toBinaryString(num);
    System.out.println(“Binary vesrion is : “+Binary);
    }
    }

    0

  • Dhivya

    import java.util.HashMap;
    import java.util.Scanner;

    public class octal_Binary {
    public static void main(String[] args) {

    HashMap b =new HashMap();
    b.put(0,”000″);
    b.put(1,”001″);
    b.put(2,”010″);
    b.put(3,”011″);
    b.put(4,”100″);
    b.put(5,”101″);
    b.put(6,”110″);
    b.put(7,”111″);

    Scanner s= new Scanner(System.in);
    String result =” “;
    long num = s.nextLong();
    long n=num;
    while(n !=0){
    int rem=0;
    rem=(int)n%10;

    if(n!=0) {
    result = b.get(rem)+result;

    }
    n=n/10;

    }
    System.out.println(result);
    }
    }

    0

  • Yatin

    public static void main(String[] args) {
    Scanner sc=new Scanner(System.in);
    System.out.print(“Enter a OCTAL number:”);
    int octal=sc.nextInt();
    int binary=0;
    int i=1;
    while(octal!=0) {
    int decimal=octal%10;
    while(decimal!=0) {
    int temp=decimal%2;
    binary=binary+temp*i;
    decimal /=2;
    i *=10;
    }
    octal /= 10;
    }
    System.out.println(binary);

    1