Binary to octal conversion using Java
Binary to Octal Conversion
In this article we will discuss binary to octal conversion using java. For this purpose we need to ask a binary number from user and convert that binary number to its octal equivalent form and then print the converted number on to the screen.
For conversion, we first convert the binary number into decimal form and then convert the decimal number to octal number. For better understanding with an example just have a look towards the diagram shown at the right.
Method discussed
We will first convert the Binary number into Decimal and then convert the Decimal number into Octal
Make sure that you have gone through these approaches below –
Run
//Java program to convert binary number to octal number
import java.util.Scanner;
public class Main
{
public static void main(String args[])
{
//scanner class object creation
Scanner sc = new Scanner(System.in);
//input from user
System.out.print("Enter a binary number : ");
int binary = sc.nextInt();
//Declaring variable to store decimal number
int decimal = 0;
//Declaring variable to use in power
int n = 0;
//writing logic for the conversion from binary to decimal
while(binary > 0)
{
int temp = binary%10;
decimal += temp*Math.pow(2, n);
binary = binary/10;
n++;
}
int octal[] = new int[20];
int i = 0;
//writing logic for the conversion from decimal to octal
while(decimal > 0)
{
int r = decimal % 8;
octal[i++] = r;
decimal = decimal / 8;
}
//printing result
System.out.print("Octal number : ");
for(int j = i-1 ; j >= 0 ; j--)
System.out.print(octal[j]);
//closing scanner class(not compulsory, but good practice)
sc.close();
}
}
Method 1 Code
Output :
Enter binary number: 1010
Decimal : 10
Octal : 12
Method 2:-
Method 2 uses the concept of grouping 3 successive digits/bits of the binary number and calculating octal digits against each grouping
We use an additional array to store the octal digits at each index.
We will need to print the array in reverse to get actual octal equivalent.
Method 2 Code
Run
//Java program to convert binary number to octal number
import java.util.Scanner;
public class Main
{
public static void main(String args[])
{
//scanner class object creation
Scanner sc = new Scanner(System.in);
//input from user
System.out.print("Enter a binary number : ");
int binary = sc.nextInt();
//Declaring variable to store decimal number
int decimal = 0;
//Declaring variable to use in power
int n = 0;
//writing logic for the conversion from binary to decimal
while(binary > 0)
{
int temp = binary%10;
decimal += temp*Math.pow(2, n);
binary = binary/10;
n++;
}
int octal[] = new int[20];
int i = 0;
//writing logic for the conversion from decimal to octal
while(decimal > 0)
{
int r = decimal % 8;
octal[i++] = r;
decimal = decimal / 8;
}
//printing result
System.out.print("Octal number : ");
for(int j = i-1 ; j >= 0 ; j--)
System.out.print(octal[j]);
//closing scanner class(not compulsory, but good practice)
sc.close();
}
}
Output :
Enter binary number: 10101111
257
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String num = sc.nextLine();
try{
int decimal= Integer.parseInt(num,2); // binary to decimal conversion.
String octal=Integer.toOctalString(decimal);
System.out.println(octal);}
catch (Exception e){
System.out.println(“Invalid binary input. Please enter a valid binary number.”);
}
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import java.util.*;
public class Binarytooctal {
public static long binarytodecimal(int binary){
long decimal =0;
int x=0;
while(binary >0){
long rem = binary %10;
decimal += rem * Math.pow(2,x);
binary /=10;
}
return decimal;
}
public static List decimaltooctal(long decimal){
List a = new ArrayList();
long octal =0;
while(decimal >0){
long rem = decimal % 8;
a.add(rem);
decimal /=10;
}
return a;
}
public static void main(String[] args){
System.out.print(decimaltooctal(binarytodecimal(111)));
}
}
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import java.util.*;
public class Binary_Octal
{
public static void main(String args[])
{
Scanner sc=new Scanner(System.in);
System.out.println(“Enter a Binary number : “);
int num=Integer.parseInt(sc.nextLine(),2);
String octal=Integer.toOctalString(num);
System.out.println(“Octal version is : “+octal);
}
}
import java.util.*;
class main{
static String octal(String binary){
int temp = 0;
StringBuilder octal = new StringBuilder();
int j = 0;
for(int i=binary.length()-1;i>=0;i–){
if(j == 3){
octal.append(temp);
System.out.println(j+” “+temp);
temp = 0;
j=0;
}
temp += (binary.charAt(i)-‘0’)*Math.pow(2,j);
j++;
}
octal.append(temp);
return “Binary : “+binary+” == octal : “+octal.reverse().toString();
}
public static void main(String[] args) {
String binary = “1011001”;
System.out.println(octal(binary));
}
}
package com.company;
import java.util.*;
class Main {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.println(“enter the binary number”);
int binary=input.nextInt();
int l=0,b=0;
int decimal=0;
int octal=0;
while(binary!=0)
{
b=binary%10;
decimal=decimal+(b*((int)Math.pow(2,l)));
binary=binary/10;
b=0;
l++;
}l=0;
System.out.println(“decimal”+decimal);
while(decimal!=0)
{
b=decimal%8;
// System.out.println(b);
octal=octal+(b*(int)Math.pow(10,l));
// System.out.println(octal);
decimal=decimal/8;
l++;
// System.out.println(decimal);
}
System.out.println(“octal”+octal);
}
}