IBM Coding Questions and Answers 2025 | PrepInsta

February 3, 2025

IBM Coding Questions 2025

Here You can get all the IBM Coding Questions and Answers of IBM Coding Round.

Find All the latest 2025 IBM Coding Questions and Test Modules for Coding Round in IBM below.

 
IBM Coding Questions 2 Questions
Total Time55 mins
Types of TestNon Adaptive
Negative MarkingNo
IBM Coding Questions

IBM Coding Test Questions and Answers 2025

Total Number of Questions:-6 ( 2 Coding Questions)

Total Time Limit:-55 Mins

Coding

  • C
  • C++
  • JAVA
  • Python

MCQ’s

  • DBMS
  • Data structure
  • Computer Networks
IBM Coding TestNumber of Questions
Code2 Questions

IBM PROGRAMMING PREVIOUS YEAR  QUESTIONS AND ANSWERS

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  2. IBM Java Programming Questions for On Campus
  3. IBM C++ Programming Questions for On Campus

IBM Coding Questions and Paper 2025

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IBM Coding Questions and Answers

1. Write a program to find HCF of two numbers by without using recursion.

Input format:

The first line contains any 2 positive numbers separated by space.

Output format:

Print the HCF of given two numbers.

Sample Input:

70 15

Sample Output:

5

 

Run 
#include<iostream>
int gcd(int,int);
int main()
{
    int m,n,ans;
    scanf("%d",&m);
    scanf("%d",&n);
    while(m!=n)
    {
        if(m>n)
        {
            m=m-n;
        }
        else
        {
            n=n-m;
        }
    }
    printf("%d",m);
    return 0;
}

Q2. Consider a string, S, that is a series of characters, each followed by its frequency as an integer. The string is not compressed correctly, so there may be multiple occurrences of the same character. A properly compressed string will consist of one instance of each character in alphabetical order followed by the total count of that character within the string.

Run 
import java.util.*;

public class Main {
    public static String properCompression(String s) {
        StringBuilder compressedStr = new StringBuilder();

        for (int i = 0; i < s.length(); i += 2) { char c = s.charAt(i); int count = Character.getNumericValue(s.charAt(i + 1)); while (count > 0) {
                compressedStr.append(c);
                count--;
            }
        }

        return compressedStr.toString();
    }

    public static void main(String[] args) {
        String inputStr = "a3b5c2a2";
        String compressedResult = properCompression(inputStr);
        System.out.println(compressedResult);  // Output: "aaabbbbbcc"
    }
}

Q3. Write a  C++ Program to Change Decimal Number to Binary?

Run 
#include<iostream>
namespace std;
int main ()
{
  int a[10], n, i;
  cout << "Enter the number to convert: ";
  cin >> n;
  for (i = 0; n > 0; i++)
    {
      a[i] = n % 2;
      n = n / 2;
    }
  cout << "Binary of the given number= ";
  for (i = i - 1; i >= 0; i--)
    {
      cout << a[i];
    }
}

Q 4.C++ Program to generate Fibonacci Triangle

Run 
#include<iostream>  
using namespace std;  
int main()  
{  
    int a=0,b=1,i,c,n,j;    
    cout<<"Enter the limit: ";   
    cin>>n;    
    for(i=1; i<=n; i++)    
    {    
        a=0;    
        b=1;    
        cout<<b<<"\t";   
        for(j=1; j<i; j++)   
        {    
            c=a+b;    
          cout<<c<<"\t";    
            a=b;    
            b=c;  
        }    
        cout<<"\n";    
    }  
    return 0;  
}  

Q 5. What is the Output of the program

Run

include
Using namespace std;
int main()
{
  int a=5,b=10,c=15;
  int*arr[]={&a,&b,&c};
  cout<<arr[1];
  return 0;
}
  • 5
  • 10
  • 15
  • It will print their address of variable b.

Q 6. What is the Output of the program

Run

include 
Using namespace std;
int main()    
{
  Char arr[20];
  int i;
  for(i=0;i<10;i++)
  *(arr+i)=65 +1;
  *(arr+i)=0;
  cout<<arr; 
  return(o); 
}
  • ABCDEFGHIJ
  • AAAAAAAAAA
  • JJJJJJJJ
  • None of the above
Solution:-A

Q 7. What is the Output of the program

Run

 

#include<iostream> 
Using namespace std;
int main()
{
  char*ptr;
  Char Str[]="abcdefg";
  ptr=Str;
  ptr+=5;
  cout<<ptr;
  return 0;
}
  • fg
  • cdef
  • defg
  • abcd

Q8. For each element of an array of non-negative integers, arrin], is calculated as:
prefli] = arr[1JIJ⊕ arrl2JIJO . . . ⊕arrli]
Here x ⊕ y is the bitwise XOR of x and y. The array pref[n] contains the prefix XOR of all elements in arr[n]where 1 s is n.
1
2
Given the array pref, find the original array arr.
Note: There is always a unique arr for a given pref.

Run 
public class Main {
    public static int[] findOriginalArray(int[] pref) {
        int n = pref.length;
        int[] arr = new int[n];
        
        arr[0] = pref[0];
        for (int i = 1; i < n; i++) {
            arr[i] = pref[i] ^ pref[i - 1];
        }
        
        return arr;
    }

    public static void main(String[] args) {
        int[] pref = {3, 5, 2, 10};
        int[] originalArray = findOriginalArray(pref);
        
        System.out.print("Original Array: ");
        for (int num : originalArray) {
            System.out.print(num + " ");
        }
        // Output: Original Array: 3 8 10 2
    }
}

FAQ

Question : What is the Difficulty Level of the Coding Paper of IBM?

Answer: The Coding paper difficulty is Medium to High is IBM Coding Test. If you want to prepare you can Prepare from our website Prepinsta.com

Question : In Which Languages You can solve the IBM Coding Test Paper?

Answer: You Can use these langugaes to solve Coding Test of IBM

  • C
  • C++
  • JAVA
  • Python

Question : How to Prepare for IBM Coding Test Paper?

Answer: You can Visit our website for IBM Coding Test paper.You will get many questions to solve the paper.

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7 comments on “IBM Coding Questions and Answers 2025 | PrepInsta”


  • kalikrishna038

    By reading the qn,I think the code for Q2 is wrong.
    import java.util.*;

    public class Main {
    public static String properCompression(String s) {
    StringBuilder compressedStr = new StringBuilder();
    int freq[] = new int[26];
    for(int i=0;i<s.length();i+=2){
    freq[s.charAt(i)-'a']+=(s.charAt(i+1)-'0');
    }
    for (int i = 0; i < 26; i ++) {
    char c = (char)(i+'a');
    int count = freq[i];
    if(count!=0)compressedStr.append(c+""+count);
    }

    return compressedStr.toString();
    }

    public static void main(String[] args) {
    String inputStr = "a3b5c2a2";
    String compressedResult = properCompression(inputStr);
    System.out.println(compressedResult); // Output: "a5b5c2"
    }
    }