CoCubes Visual Reasoning Question and Answers Quiz-1

Half circle is made at the edges of the triangle, so when reopened, the complete circles will appear at the three sides, so three complete circles will be appeared in the answer figure resembling the three sides of the triangle.
A is the correct answer

Sol. (d) The figures form a series. The complete figure rotates 90° CW in each step. Fig. (d) does not fit in the series as it is the same as fig. (b). Hence fig. (d) is the answer.

Option C

Explanation: This is an alternating series. In the first segment, the letter "E" faces right, then down, then right. In the second segment, the letters all face down. To follow this pattern, in the fourth segment, the letters must all face up.

Answer: Option B

Explanation: Notice that in each segment, the figures are all the same shape, but the one in the middle is larger than the two on either side. Also, notice that one of the figures is shaded and that this shading alternates first right and then left. To continue this pattern in the third segment, you will look for a square. Choice b is correct because this choice will put the large square between the two smaller squares, with the shading on the right.

Option D

Explanation: This is an alternating series. The first and third segments are repeated. The second segment is simply upside-down.

Option D

Explanation: Look for opposites in this series of figures. The first and second segments are opposites of each other. The same is true for the third and fourth segments.

Answer: Option C

Explanation: In this series, the shaded part inside the circle gets larger and then smaller.

Answer: Option A

Explanation: Look at each segment. You will notice that in each, the figure on the right and the figure on the left are the same; the figure in between is different. To continue this pattern in the last segment, the diamond on the left will be repeated on the right. Choice a is the only possible answer.

The triangles are:

∆ABF: ∆AGB: ∆AGF: ∆BFC;

∆BCE: ∆CEF: ∆BFE: ∆HBC;

∆HCE: ∆HEF: ∆HBF: ∆BGH;

∆FGH: ∆HCD:∆HDE:∆AFH;

∆ABH:

Therefore correct option is b